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Passing command output as an argument to a shell script

 
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# 1  
Old 03-24-2010
Bug Passing command output as an argument to a shell script
Hi,

I have a very small requirement where i need to pass command output as an argument while invoking the shell script..

I need to call like this
Code:
sh testscript.sh ' ls -t Appl*and*abc*  | head -n 1'

This will list one file name as ana argument..

I will be using "$1" in the shell script..

Please suggest a good way to invoke the script ..

Thanks in Advance,
SandeepSmilie
Last edited by vbe; 03-24-2010 at 11:42 AM.. Reason: code tags
# 2  
Old 03-24-2010
Please state what shell you are using?

Quote:
sh testscript.sh ' ls -t Appl*and*abc* | head -n 1'

This will list one file name as ana argument..
It won't. The single quotes '' will stop execution of the "ls" command line and pass the whole "ls" command line intact as a parameter to testscript.sh.
What is the contents of "testscript.sh"? Does it contain an "eval" command?

I think we need to know in words what you are trying to achieve?
Consider what input you will provide, what processing is required, and what output you expect.
# 3  
Old 03-24-2010
Hey,

Thanks for the reply.

I need to pass a file name as an argument while invoking the shell script..

In the test script i am using that file name to check if it exists and then determine its properties like file size,word count,no of records

i am not using an "eval" in the script..

I want to know how i need to give the argument .. like it should evaluate ang give the file name as argument while calling the shell script..

let mw know if it calrifies ur question

Thanks,
Sandeep
 
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