UNIX for Dummies Questions & Answers

Hi,

I have a file with:

Param1="JobID=1234"
Param2="Company=ABC"
Param3="Address=Sunnyvale,CA"

I'd like to get the value of the JobID. Can you please help me the best way to do that?

Thanks in advance.

Code:

head -1 file | cut -c 15-18

Try this,

Code:

head -1 file | cut -d "=" -f 3 | sed -e 's/"//'

Or just awk...

Code:

awk -F"\"|=" '/JobID/{print $4}' infile

Thanks for the solutions. I prefer the awk since I am not restricted to get the JobID only. I may also need to get values of other parameters. However, I am having problem when I have another parameter with the text 'JobID' in it such as:

Param1="JobID=1234"
Param2="Company=ABC"
Param3="Address=Sunnyvale,CA"
Param4="OldJobID=5678"

Can you tweak the awk a little please? Thanks in advance.

Using standard unix commands:

Code:

Param1="JobID=1234"
eval "${Param1}"
echo "${JobID}"
1234

Yea, like this...

Code:

awk -F"\"|=" '$3=="JobID"{print $4}' infile

Or sed can do it too...

Code:

sed -n 's/.*\"JobID=\([0-9]*\).*/\1/p' infile