UNIX for Dummies Questions & Answers

Hi, I'm executing a script to check if a file has been modified on a shared folder.
I use this to start another script every time the file has been modified.
To do this I use the 'ls' command to get the last modification date of the file.

My problem is that the computer hosting the shared folder has not the same system time (1 hour less) than the computer on which I'm executing the 'ls' command.
So once the file is modified I only get the year instead of the hour.
I know this is a normal situation as described in the man: "If the modification time of the file is more than 6 months in the past or future, then the year of the last modification is displayed in place of the hour and minute fields."

Then one hour later the 'ls' command give me the hour of the modification because I'm not anymore in the future.
As the 'ls' command returns the hour and not the year, my script considers the time is different and so the file has been modified.
And so my second script is started again (even it's not needed).

Is there a way to force the 'ls' command to always returns the hour? or is there another way to know that a file has been modified?

I'm working on Solaris, HP, AIX and Linux.

Thanks in advance.

This works on any UNIX platform with perl.
https://www.unix.com/shell-programmin...ime-files.html

Please post:

Code:

echo "${TZ}"
date
ls -la /name_of_the_local_directory
ls -la /name_of_the_shared_directory

If you want to find the last modification time of a file, you can use the "stat" function.

Code:

use strict;
use warnings;

my $filename="filename";
  my ($dev,$ino,$mode,$nlink,$uid,$gid,$rdev,$size,$atime,$mtime,$ctime,$blksize,$blocks);

  ($dev,$ino,$mode,$nlink,$uid,$gid,$rdev,$size,$atime,$mtime,$ctime,$blksize,$blocks) = stat($filename);

  system("date -d\@$mtime");

Try:
[May not be available in all *nix flavours]

Code:

stat file | awk -F"[: ]" '/^Modify/ {print $4; }'

Thanks for all the replies, I'll try all this on Monday and let you know.