UNIX for Dummies Questions & Answers

Hi All,

I am using korn shell sun solaris 10

What i need is i have to grep one file and if there are any finding then i have set one flag. otherwise continue

Please help

Regards
Arun

Your question, like the subject of the thread is very vague.

Please elaborate.

I've moved your thread to a shell scripting forum, as this is not a Solaris question.

Ok thank you scott.

As i said i need to grep one file for perticular word like "ORA-"
If any rows found with that word then set flag x=1
else
set flag =0

Code:

grep ORA- > /dev/null some_file && x=1 || x=0

Please post the latest version of you script, whether or not it contains syntax errors.

Please post examples of lines from the log which contain the string "ORA-".


This command sequence is not valid in any unix script:

Code:

set flag x=1
else 
set flag =0

It is not possible to guess what you want to do.
Please state in words (not script) what you are trying to do showing example input and example output with a statement about the processing.

actually i meant that in words... not as a script

---------- Post updated at 06:27 PM ---------- Previous update was at 06:20 PM ----------

Thanks scott.. what u said is working for me

If i have many search strings? then? like 'ORA-','Warning','Error'

Please advice

You can use

Code:

grep -E "ORA-|Warning|Error"