UNIX for Dummies Questions & Answers

Hi all,

I've got the following piece of code which performs my FTP functionality. My issue is that despite the fact that both standard out and standard error out are defined, I still get a single line of output on the screen when I run the script. i.e. it may be:

530 Login incorrect.
553 /home/user/testing/test.sh: A file or directory in the path na
me does not exist.

How can I stop these single line messages from appearing? The code I'm currently using is below:

<code>
/usr/bin/ftp -ivn ${DEST_SERVER} << EOF > ${FTP_LOG} 2>&1
user ${DEST_USER} ${DEST_PWORD}
copylocal
put ${FILE} ${DEST_PATH}${tmpTrimFile}
bye
EOF
</code>

The script is written in KSH

Cheers,
Linden

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Hi drunna,

Thanks very much much for your reply. Unfortunately your suggestion didn't help me - I still got the same response outputted to the screen.

I also tried removing the -v flag from ftp, however, all that did was remove the number at the start of the output.
e.g. "530 Login incorrect." became "Login incorrect."


Can anyone shed some light on this for me?

Cheers,
Linden

I cannot duplicate your results. My output goes to my log file. And the order of redirection did not matter.

I used ksh on hp-ux 11i.

Are you sure that FTP_LOG is set properly?

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This is quite bizarre (or atleast for me anyway). I tried the ftp piece of code in a script by itself and didn't see the output. (i.e. as I want it). Thus, it's not a machine thing.

I also made sure that the log file was being created correctly, and it was. I'm going in for further testing, but I'm quickly running out of ideas.

Any other suggestions?

Cheers,
Linden

OS: AIX

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