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grep for a last word from a path

 
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# 1  
Old 02-04-2010
grep for a last word from a path
Hi ,
I want to get the last word from a path.

Example::
I have path::
/TEMP_REGRESSION/regression/TESTSUITE/TestCases/Test1201/ext_libs/DATA/INTERNAL/pad_ext.lef

I want the last word only.ie pad_ext.lef

Please let me know how to grep that word.
Thanks in advance
# 2  
Old 02-04-2010
Hi.

Code:
$ X=/TEMP_REGRESSION/regression/TESTSUITE/TestCases/Test1201/ext_libs/DATA/INTERNAL/pad_ext.lef
$ echo ${X##*/}
pad_ext.lef

Last edited by Scott; 02-04-2010 at 10:25 AM..
# 3  
Old 02-04-2010
Quote:
Originally Posted by scottn
Hi.

This has been asked many times. You could search the forums.

Code:
$ X=/TEMP_REGRESSION/regression/TESTSUITE/TestCases/Test1201/ext_libs/DATA/INTERNAL/pad_ext.lef
$ echo ${X##*/}
pad_ext.lef


Hi Scott,
Thanks a lot for your fast replySmilie
Regards,
Neelam G
# 4  
Old 02-04-2010
Or with awk:

Code:
X="/TEMP_REGRESSION/regression/TESTSUITE/TestCases/Test1201/ext_libs/DATA/INTERNAL/pad_ext.lef"

echo $X | awk -F'/' '{print $NF}'

# 5  
Old 02-04-2010
Why use awk when a simple basename is sufficient?
# 6  
Old 02-04-2010
MySQL
Because I didn't know about the basename command? Smilie

But you're right, it's the best for this task, since this is what it's designed to do.

Thanks for the heads up.
# 7  
Old 02-23-2010
MySQL
The following ways we can achieve your requirement.


1. Using cut

Code:
cut -d '/' -f 10 path

2.1 Using grep

Code:
grep --color '/\([^/]*\)$' file name

Output:

/TEMP_REGRESSION/regression/TESTSUITE/TestCases/Test1201/ext_libs/DATA/INTERNAL/pad_ext.lef

2.2 Using grep
Code:
grep --color -o '\([^/]*\)$' filename

Output:
pad_ext.lef
 
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