expr - Syntax error


 
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# 1  
Old 01-19-2010
expr - Syntax error

hello to everyone,
i am writing a shell script in unix and i use the following command:
Code:
lnum= cut -f 1 -d : aa
passline=`expr $lnum + 1`
echo "$passline"

with the following command i get the value that is stored in the first field of the file "aa" and i save it in the variable "lnum". i am sure that this works because if i just echo "lnum" then i can see the numbers i want to see.
the problem is with the expr because when i run the script it writes me:

expr: 0402-050 Syntax error

i cannot find what is the problem because i search everywhere and i cannot find a syntax error in this.
do you have any suggestion?

thank you for your time

Last edited by Franklin52; 01-19-2010 at 05:19 AM.. Reason: Please use code tags!
# 2  
Old 01-19-2010
Code:
lnum= cut -f 1 -d : aa

will give you the correct output but will not store it in variable lnum
This will:
Code:
lnum=$(cut -f 1 -d : aa)

# 3  
Old 01-20-2010
i tried it and it worked!
thank you!
 
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