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Proper Expression To Not Include A String...

 
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# 1  
Old 12-23-2009
Proper Expression To Not Include A String...
I have a folder of scripts:

Code:
bash:/folderpath/> ls
beginFile.sh
beginFileBackup.sh
beginAnother.sh
beginAnotherBackup.sh
beginJunk.sh
beginJunkBackup.sh

I'd like to be able to call just one (beginFile.sh) using this type of scheme:

Code:
#Run the beginFile script without the word "Backup" in it.
echo /folderpath/beginFile[^Backup]*.sh | xargs -n1 sh
#Run the rest of scripts with the exception of the beginFile.sh script.
echo /folderpath/begin[^File[^Backup]]*.sh | xargs -n1 sh

Also, what If I did it this way:

I know it isn't right, but can anyone provide the correct syntax? Also what If I want to run the rest of the scripts, except the beginFile.sh and the *Backup.sh file (i.e. beginAnother.sh and beginJunk.sh)?


Code:
ls /folderpath | grep 'begin[^File.sh]' | xargs -n1 sh

Would the expression change because I'm using grep?


Thanks in advance for all answers.
Last edited by mrwatkin; 12-23-2009 at 04:43 PM..
# 2  
Old 12-23-2009
If you set extglob (shopt) to yes in bash, or standard in ksh93 you can do this:

Just run beginfile:
Code:
/folderpath/beginFile.sh

run he rest of the scripts:
Code:
/folderpath/!(beginFile.sh)

run the rest of the scripts, except the beginFile.sh and the *Backup.sh file
Code:
/folderpath/!(beginFile.sh|*Backup.sh)

Last edited by Scrutinizer; 12-23-2009 at 05:16 PM..
 
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