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grep a file from a given line only

 
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# 1  
Old 12-09-2009
grep a file from a given line only
Hi all,
I'm looking for the line number where the string "total" appears.
I know that this is after a given line number which I know.
So I would like to know the line number of the first "total" after the line X.

Is it possible to use grep a file from a given line only?
Thank you,
# 2  
Old 12-09-2009
what have you tried?
# 3  
Old 12-09-2009
Try:

If looking for a pattern 404 after line 10

Code:
awk 'NR>10 && /404/ { print NR;exit; }' file

# 4  
Old 12-09-2009
awk has neat built in variable like NR which you could use, together with it's pattern matching capabilites. Something like (assuming your line number is 258):

Code:
awk 'NR >= 258 && /<total>/ {print NR; exit}' infile

# 5  
Old 12-09-2009
I tried

Code:
        N_LINES_TO_READ=`grep -n total file | head -1 | cut -d : -f 1`

but this is on the whole file. I would like to start that operations say fom line 1000.
I looked for grep options but I didn't find any obvious way to do it.
# 6  
Old 12-09-2009
check your version of tail and see if you can invoke
Code:
tail -n +1000 file

this says start from 1000th line onwards. Now you can grep with head -1.
# 7  
Old 12-09-2009
Here is what I came up with (thanks also to your help)

Code:
        file=${1}-0${EXT}.out_bis
        awk "/$var1/ && (++x==$OCCURRENCE){ print NR}"  $file
        awk "NR>19719 && /total/ { print NR;exit; }"  $file

This works, I get the line numbers on the screen
I tried this because I need the line numbers as a variables

Code:
        LINE=`awk "/$var1/ && (++x==$OCCURRENCE){ print NR}  $file"`
        END_LINE=`awk "NR>$LINE && /<total>/ { print NR;exit; }  $file"`

But it gets stuck!
Thank you again,
 
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