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nawk: syntax error at source line 11

 
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# 1  
Old 12-09-2009
nawk: syntax error at source line 11
Hi,
I executing a awk in a shell script. A part of AWK is:

Code:
nawk -F"¤" -v fichero=${DIRECTORIO_PARAMETROS}/${FICHERO_CONFIGURACION_CHEQUEOS} -v sistema=${SISTEMA_SEDRA} -v fichero_no_validos="No_validos_CAMPO_TIPO_${SIST}.dat"  'BEGIN{
 if  ( fichero != "")                               
 {                                                  
         while ( ( getline < fichero ) > 0 )        
         {                                          
                configuracion [$1] = $2                
         }                                          
 } 
 
  tipo=configuracion [sistema"_CAMPO_TIPO"]
 exit=0                                        
}

But obtain this error:

Code:
nawk: syntax error at source line 11
 context is
         >>>    exit= <<< 0
nawk: illegal statement at source line 11

Because this error can happened?
# 2  
Old 12-09-2009
you can use exit 0 in place of exit=0

Thanks
Penchal
# 3  
Old 12-09-2009
Thanks,

With that solves that error code. But later I find the following code:

Code:
if (( NF != configuracion [sistema"_"producto"_CAMPOS"] ) && ( exit=="0" ))
  {
   printf "El número de campos no es correcto para la línea %s\n",$0 >> fichero_no_validos
   exit=1
  }

Code:
nawk: syntax error at source line 30
 context is
         >>> it <<< =="0" ))
nawk: illegal statement at source line 30


As in this case could solve the problem?

Thanks.

---------- Post updated at 07:38 AM ---------- Previous update was at 03:56 AM ----------

Anybody know a solution?

Thanks! and sorry
# 4  
Old 12-09-2009
"exit" is a builtin. Use something else like exit_code for user defined variable.
# 5  
Old 12-10-2009
Quote:
Originally Posted by binlib
"exit" is a builtin. Use something else like exit_code for user defined variable.
Thanks, Already solved it.
 
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