UNIX for Dummies Questions & Answers

Problem - ive just noticed ive written the date format wrongly - does this make a difference?

I should have written
200307072003070420030707

This is the format that the script will have to read. Can i change the script to yyyymmdd????


This is the format it will always take i.e with the 01, 02 ....

On the script you said would work does the data_file refer to the path name where this file is held. Do i replace data_file with the pathname?

Thanks

You could very well change the sequence, just read the man page for *date*, it has more informations

date -u +%Y%m%d

data_file is the file in which you have your sequence of dates ie

20030707.........................

Regards
JK

Forgive me but ive never actually created a script
if i login to unix session and enter the script as it is

#!/bin/ksh
FILE_DATE=$(cut -c 9-15 ../../../data_file | head -1)
TODAYS_DATE=$(date +'%Y%m%d)

if [ ${FILE_DATE} != ${TODAYS_DATE} ]
then
echo "Dates Dont Match"
fi

then this will work. (Idont have to enter anything else?)
Do i just save it and then call it up with autosys?

Thanks - in advance

Yes, this should work, but you should use a full path to the file name. I dont usually use relative paths. Also, if your date file only has 1 line in it then you can remove the | head -1 as this simply makes sure that the only 1 row is returned. Before adding it to the autosys queue, I would test it by running it! Make sure to give it executable permissions (chmod command).
By the way, data_file represents your file name. Change this to the name you call your file.

Also, this is very simple script, you may want to add some things to it such as a log file. The echo command "Dates dont match" will echo to standard out and will most certainly be missed by everyone. Redirect the output to a file, or have the script mail you a message if the dates do not match. There are many examples of mail scripts on these boards. Search them out. Good Luck

Thanks for your help

I dont know about the chmod but i'l look it u in man n give it a go.

Thanks!

this program assumes the following:
1) the pattern you are looking for is 8 charicters from the beginning of the line.

provided that condition is met this does what you need.

1) open a text editor and past the below code in it.
2) save the file and exit the editor
3) chmod 755 file_you_just_made
4) to execute the file type "./file_you_just_made FILE_TO_SEARCH DATE_TO_MATCH

5) if the date is NOT found you get an error on your screen
5a) if date IS found it exits quietly

Code:

#!/usr/bin/perl -w
#200307072003070420030707

use strict;

if ($#ARGV != 1) { print "Usage: ./script file_to_search date_to_search\n"; exit };
my $file=shift;
my $date=shift;

open (FILE, "$file") or die "Can not open the file ($!)";
my @data=<FILE>;
print "ERROR No proper date found\n" if (! grep /^........$date/, @data) ;

Hi there!!

Since discovered that this file has more than one line that it has to check!!

The format of the file looks like

MP 000000000000000000000000 200307072003070420030707000000000000000000
00000000.000000000000000.0000000000000000000000000000000000000000

MP 0000000000000000000000000 200307072003082920030707000000000000000000
00000000.000000000000000.0000000000000000000000000000000000000000

MP 000000000000000000000000 200305212003121720030521000000000000000000
00000000.00000000000000000000000000000000000000000000000000000000

There are somethin in the region of 9 of these sets of lines in a file. All of which should have the ssame date.
Didnt get the chance to try the first set of solutions unfortunatley so really not sure n how i would manage to get this to work.

Is it possible??
Can anyone help please??

To recap ive to get a script to check this file in particular the 200305212003121720030521 and to check the middle date in this = todays date and if not then raise an alert (which already exists so im assuming i just put in a pathname to the script)

Thanks in advance.