Quote it from where you are sending.... Again quoting is the answer.
Example:
Process 1: Get and prints the argument.
Code:
$ cat get-arg.sh
echo $1 $2
File: f1 is the file which has the given content
Code:
$ cat f1
products/100% Haddock Fillets 500G-small.gif
products/100% Haddock Fillets 500G.gif
products/2 Hot and Spicy Grills 200G -small.gif
products/2 Hot and Spicy Grills 200G.gif
products/2 Original Fillet Burgers 180G -small.gif
products/2 Original Fillet Burgers 180G.gif
Process 2: Reads lines, and calls the other process with the argument.
Code:
$ cat t1.sh
while read line
do
#echo $line
sh ./get-arg.sh "$line"
done < ./f1
Note: When "" around line is there then it had been taken as a single argument...
I hope you have got it now as because i demonstrated enough ....
If needed, give without QUOTE in $line, then you will printing only first two words...
With Quote:
Code:
$ sh t1.sh
products/100% Haddock Fillets 500G-small.gif
products/100% Haddock Fillets 500G.gif
products/2 Hot and Spicy Grills 200G -small.gif
products/2 Hot and Spicy Grills 200G.gif
products/2 Original Fillet Burgers 180G -small.gif
products/2 Original Fillet Burgers 180G.gif
Without Quote:
Code:
$ sh t1.sh
products/100% Haddock
products/100% Haddock
products/2 Hot
products/2 Hot
products/2 Original
products/2 Original
Hello,
I am trying to execute remote script with ssh :
ssh -o ConnectTimeout=10 -o PasswordAuthentication=no -o NumberOfPasswordPrompts=0 -o StrictHostKeyChecking=no root@host '/arbo/script -t'
My script is well executed, but my option '-t' is never loaded, how can you explain that ? (2 Replies)
I have a simple bash script on RHEL that works fine when there is one file but when it finds multiple files of same condition I get too many args error.
for i in *
do
if ;then
echo "no files to move"
exit 0
fi
if ; then
... (10 Replies)
Hello, I've just started with shell scripting, and I need som assistance!
Basicly what I want to do is copy names from one file to another, when running the scrip the user should be asked about the status of these names.
Let me demonstrate:
file:
Name: John, Gender: male
Name: Jane,... (6 Replies)
Hello All,
I am trying to find a file name with .sh exention from a list of .dat files inside a directory.
find /app/folder1/* -name '*.dat'| xargs grep '.sh'
ksh: /usr/local/bin/find: arg list too long
Please help me finding the command.
Thanks (3 Replies)
Hi,
Help. I have a file that contains a list of users in a file. I want to cat the content of the file and feed it into sed to a preformated report. The error I got is "ksh: /usr/bin/sed: arg list too long" My method below.
A=`cat FILE1.txt`
B=`echo $A`
sed "s#USERLIST#$B#" FILE2 >... (2 Replies)
Aix 5.2 on a P510 RS6000
My /usr filesystem is sized at 3.8 gb. Check me if I'm wrong here but this should be enough space for /usr?
When I installed the o/s I just followed the defaults, didn't add any 3rd party apps, least that I know of.
My problem is that it's running at 90% capacity. ... (2 Replies)
I do ls -l ABC*, I get arg list too long message. This will not happen if ABC* has small no of files I believe 4000 files is limit. Any way of avoiding this.
I even tried like this
for i in `ls -l ABC*`
do
echo $i
done
Same problem.
Any solution would be great.
I am on HP-UX... (5 Replies)
