Login or Register to Ask a Question and Join Our Community


UNIX for Dummies Questions & Answers

Grep -v, with -A or -B?

 
Thread Tools Search this Thread
Top Forums UNIX for Dummies Questions & Answers Grep -v, with -A or -B?
# 8  
Old 10-24-2009
Haha. Sorry I completely missed the point Smilie Hang on!
# 9  
Old 10-24-2009
lol, it's ok, at least you understand what i mean now, sorry for not being clear in what i was trying to accomplish
# 10  
Old 10-24-2009
Code:
awk -v A=-1 '/figure/ { A = 1 } A-- >= 0 {next } 1' file1

Change A = 1 to another number depending on how many lines you want to skip.

(still looking at grep option!)
# 11  
Old 10-24-2009
Quote:
Originally Posted by scottn
Code:
awk -v A=-1 '/figure/ { A = 1 } A-- >= 0 {next } 1' file1

Change A = 1 to another number depending on how many lines you want to skip.

(still looking at grep option!)
awk?, i've never heard of this command, however it gets the job done, i'll look into it more, thanks for the help
# 12  
Old 10-24-2009
It seems to me grep is working as intended. The example is:

Code:
$> grep -v -A 1 'figure' test
This is a test of grep
to see how inversion really works
and figure out the problem that the class is having
hopefully this works

But this expected behavior if we take a look at the same command without the -A option:
Code:
$> grep -v 'figure' test
This is a test of grep
to see how inversion really works
hopefully this works

So the -A option works correctly since the line "and figure out ..." gets printed as a context to the second matched line.

If we take an example where only the first line gets output:
Code:
$> grep -v l test
This is a test of grep

With -A the result becomes:
Code:
$> grep -v l -A 1 test
This is a test of grep
to see how inversion really works

---------- Post updated at 10:06 AM ---------- Previous update was at 09:17 AM ----------

Actually one has to ask to what question the answer would be:
Code:
and figure out the problem that the class is having
hopefully this works

The question would be:

print any line that does not contain the string "figure" nor follows a line that does contain that string.
 
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Inconsistent `ps -eaf -o args | grep -i sfs_pcard_load_file.ksh | grep -v grep | wc -l`

i have this line of code that looks for the same file if it is currently running and returns the count. `ps -eaf -o args | grep -i sfs_pcard_load_file.ksh | grep -v grep | wc -l` basically it is assigned to a variable ISRUNNING=`ps -eaf -o args | grep -i sfs_pcard_load_file.ksh |... (6 Replies)
Discussion started by: wtolentino
6 Replies

2. UNIX for Dummies Questions & Answers

Piping grep into awk, read the next line using grep

Hi, I have a number of files containing the information below. """"" Fundallinfo 6.3950 14.9715 14.0482 """"" I would like to grep for Fundallinfo and use it to read the next line? I ideally would like to read the three numbers that follow in the next line and... (2 Replies)
Discussion started by: Paul Moghadam
2 Replies

3. UNIX for Dummies Questions & Answers

Bash - CLI - grep - Passing result to grep through pipe

Hello. I want to get all modules which are loaded and which name are exactly 2 characters long and not more than 2 characters and begin with "nv" lsmod | (e)grep '^nv???????????? I want to get all modules which are loaded and which name begin with "nv" and are 2 to 7 characters long ... (1 Reply)
Discussion started by: jcdole
1 Replies

4. Shell Programming and Scripting

AWK/GREP: grep only lines starting with integer

I have an input file 12.4 1.72849432773174e+01 -7.74784188610632e+01 12.5 9.59432114416327e-01 -7.87018212757537e+01 15.6 5.20139995965960e-01 -5.61612429666624e+01 29.3 3.76696387248366e+00 -7.42896194101892e+01 32.1 1.86899877018077e+01 -7.56508762501408e+01 35 6.98857157014640e+00... (2 Replies)
Discussion started by: chrisjorg
2 Replies

5. UNIX for Dummies Questions & Answers

Advanced grep'in... grep for data next to static element.

I have a directory I need to grep which consists of numbered sub directories. The sub directory names change daily. A file resides in this main directory that shows which sub directories are FULL backups or INCREMENTAL backups. My goal is to grep the directory for the word "full" and then... (2 Replies)
Discussion started by: SysAdm2
2 Replies

6. UNIX for Dummies Questions & Answers

Difference between grep, egrep & grep -i

Hi All, Please i need to know the difference between grep, egrep & grep -i when used to serach through a file. My platform is SunOS 5.9 & i'm using the korn shell. Regards, - divroro12 - (2 Replies)
Discussion started by: divroro12
2 Replies

7. Shell Programming and Scripting

grep for certain files using a file as input to grep and then move

Hi All, I need to grep few files which has words like the below in the file name , which i want to put it in a file and and grep for the files which contain these names and move it to a new directory , full file name -C20091210.1000-20091210.1100_SMGBSC3:1000... (2 Replies)
Discussion started by: anita07
2 Replies

8. UNIX for Dummies Questions & Answers

| help | unix | grep (GNU grep) 2.5.1 | advanced regex syntax

Hello, I'm working on unix with grep (GNU grep) 2.5.1. I'm going through some of the newer regex syntax using Regular Expression Reference - Advanced Syntax a guide. ls -aLl /bin | grep "\(x\)" Which works, just highlights 'x' where ever, when ever. I'm trying to to get (?:) to work but... (4 Replies)
Discussion started by: MykC
4 Replies

9. UNIX for Dummies Questions & Answers

| help | unix | grep - Can I use grep to return a string with exactly n matches?

Hello, I looking to use grep to return a string with exactly n matches. I'm building off this: ls -aLl /bin | grep '^.\{9\}x' | tr -s ' ' -rwxr-xr-x 1 root root 632816 Nov 25 2008 vi -rwxr-xr-x 1 root root 632816 Nov 25 2008 view -rwxr-xr-x 1 root root 16008 May 25 2008... (7 Replies)
Discussion started by: MykC
7 Replies

10. Shell Programming and Scripting

MEM=`ps v $PPID| grep -i db2 | grep -v grep| awk '{ if ( $7 ~ " " ) { print 0 } else

Hi Guys, I need to set the value of $7 to zero in case $7 is NULL. I've tried the below command but doesn't work. Any ideas. thanks guys. MEM=`ps v $PPID| grep -i db2 | grep -v grep| awk '{ if ( $7 ~ " " ) { print 0 } else { print $7}}' ` Harby. (4 Replies)
Discussion started by: hariza
4 Replies
Login or Register to Ask a Question