Help with GREP


 
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# 1  
Old 07-07-2009
Question Help with GREP

Hi, All -

How can I use "grep -c" command with finger/who (or some other Unix command) in order to figure out number of users currently on the system excluding the user ids starting with a/A.

(NOTE): User ids starting with a/A are the administrators. I am only interested to find out number of users connected to my system.

Thanks in advance!
# 2  
Old 07-07-2009
Code:
who | grep -cv "^[aA]"

or is a/A the actual start of the username?

Code:
who | grep -cv "^a/A"


Last edited by Scott; 07-07-2009 at 03:28 PM..
# 3  
Old 07-07-2009
SCOTTN, thanks for your reply.

The following command is working for me except for one thing. It is including the first line in the count:
Login Name TTY Idle When Where

$ finger | grep -cv '^[Tt]'
17

Is there a way to exclude the first line as well?
# 4  
Old 07-07-2009
Hi.

Yes. Finger has a header line that you need to remove.

Code:
finger | grep -Ecv '^Login|^[Tt]'

should do it.
# 5  
Old 07-07-2009
SCOTTN <<< Thanks again.

Worked like a ~charm~.

Following command works as well.

Code:
finger | egrep -cv '^Login|^[Tt]'

# 6  
Old 07-07-2009
The e stands for "extended"... some systems may not have egrep. grep -E does much the same thing.

It's like nawk and gawk. Why use them if a) awk exists and; b) it does enough for you?
# 7  
Old 07-09-2009
Use below commands...

who | grep -cv '^[aA]'

finger | grep -cv '^Login|^[aA]'
 
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