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counting the occurence of a word

 
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# 1  
Old 06-30-2009
counting the occurence of a word
In a file I have to count a particular word. like i need apache how many times.

I tried this

$ tr "\011" "\012\012"<foo1 | tr -cd "[a-zA-z\012]" |sort\uniq -c


but I got result like this

32 apache
18 dns
12 doctor


Please sugest me
# 2  
Old 06-30-2009
If all you want is the count for apache then you could do:
Code:
$ tr "\011" "\012\012"<foo1 | tr -cd "[a-zA-z\012]" | grep "^apache$" | wc -l

Update I had assumed the tr bits were working but they aren't...

Here is something that works:
Code:
$ tr "\011\040" "\012\012"<foo1 | grep -ic "^apache$"

Last edited by TonyFullerMalv; 06-30-2009 at 05:04 PM.. Reason: Workinh version!
# 3  
Old 06-30-2009
Quote:
Originally Posted by TonyFullerMalv
If all you want is the count for apache then you could do:
Code:
$ tr "\011" "\012\012"<foo1 | tr -cd "[a-zA-z\012]" | grep "^apache$" | wc -l



Thanks !!! any simpler way ?
# 4  
Old 06-30-2009
Is 'apache' the same as 'apaches' and the same as apache's or 'apache,'?
# 5  
Old 07-06-2009
Quote:
Originally Posted by vgersh99
Is 'apache' the same as 'apaches' and the same as apache's or 'apache,'?
Not if you do what I did:
Code:
grep "^apache$"

Which is looking for apache with a start of line at the beginning and an end of line at the end!
 
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