awk to parse a directory name?

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06-02-2009

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awk to parse a directory name?

Hi,

I have a directory file name:

/auto/space/user/jen/CED/CED_01MZ/visit1/DCE_2eco/016/echo1

I would like to just get the following outputs into variables such that:

variable1 = /auto/space/user/jen/CED/CED_01MZ/visit1/

and

variable2 = DCE_2eco/016/echo1

I've tried it with awk, but the solution is messy and requires some hard-coding. Any suggestions on how to make this independent of anything inside the directory filename? The only constant will be "/auto/space/user/jen/CED/CED_01MZ/". BTW, this is tcsh, not bash.

Thanks in advance!

nixjennings

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Code:

echo '/auto/space/user/jen/CED/CED_01MZ/visit1/DCE_2eco/016/echo1' | nawk -v d='/auto/space/user/jen/CED/CED_01MZ/' '$0 ~ "^" d {match($0,d "[^/][^/]*"); print "var1 = " substr($0, RSTART, RLENGTH-1) ORS "var2 = " substr($0, RLENGTH+2)}'

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constant part can be removed

Code:

echo "/auto/space/user/jen/CED/CED_01MZ/visit1/DCE_2eco/016/echo1" | sed 's#/auto/space/user/jen/CED/CED_01MZ/visit1/##g'

matrixmadhan

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