UNIX for Dummies Questions & Answers

I am running my script from "/abc/" this path and it has no ".csv files" but has a ".txt" files namely temp1.txt
My script goes as below, wherein it is suppose to find files with *.txt extension and *.csv extension in another path namely "/abc/xyz/":
#!/bin/ksh
PATH1="/abc/xyz/"
value="*.csv *.txt"
for THISTEMPLATE in $value
do
THISTEMPLATE=`echo "$THISTEMPLATE" | tr "%" "?"`
echo "thistemp = $THISTEMPLATE"
for OLDFILE in `find $PATH1 -name "$THISTEMPLATE" -type f`
do
echo "oldfile= $OLDFILE"
done
done


>OUTPUT:
thistemp = *.csv
thistemp = temp1.txt
But if you see the output the variable contains the filename "temp1.txt" instead of just "*.txt", how can i modify the script so that
the variable THISTEMPLATE takes only *.txt instead of the whole filename.

Try using single quotes to stop the shell expanding the "*" .
The line containing the "tr" command appears to be pointless.
When processing a list of filenames a while loop is better than a for loop because it can deal with unlimited names and filenames containing space characters.
Hope this helps.

Code:

#!/bin/ksh
PATH1="/abc/xyz"
for THISTEMPLATE in '*.csv' '*.txt'
do
    echo "thistemp = $THISTEMPLATE"
    find $PATH1 -name "$THISTEMPLATE" -type f | while read OLDFILE
    do
        echo "oldfile= $OLDFILE"
    done
done