UNIX for Dummies Questions & Answers

hi,
i'm trying to create a script in ksh that will check build logs for errors.
i'm using a variable to hold the grep, somthing like:

grepErr=`echo "grep -i -e ' error ' -e ' errors ' -e 'rror(s)' -e 'Unsatisfied ' -e 'Undefined symbol' -e 'No rule ' -e 'Cannot' -e 'rror:' -e 'Could not find ' -e 'No such file or directory' -e 'Unexpected end of file' -e ' Stop.' -e 'unexpected symbol' -e 'is not a member of'" '$LAST_LOG' "| grep -v 'Warning' > /dev/null"`

This variable is called in a function where the LAST_LOG var will be created.

The problem is that when i'm using grepErr in the function(after LAST_LOG is assigned a value) the value of LAST_log is not substituted.

i'm new in unix. Can someone please help me with this?

A variable between single quotes is not substituted.
There are a number of bugs in your script. It is not clear to me whether $LAST_LOG is the name of the file you will be searching or part of a string to be ignored. Also whether you want to execute grep now or later?

Anyway, this bit has unbalanced quotes and has protected $LAST_LOG from substitution:
If $LAST_LOG does not contain space characters, maybe you mean:

Code:

'is not a member of' $LAST_LOG

LAST_LOG is the file where i'm doing grep for errors
in the function i am retriving the name of the last log created and assign it to LAST_LOG:
LAST_LOG=`ls -tr hbuild.log* | tail -1`

after this i call the grep statment
$grepErr

When i delcare grepErr if i use just $LAST_LOG without ', after echo LAST_LOG is replace with "" so in the function the grep statment will fail because it will not know where to search.

the code is somthing like this

#!/bin/ksh

checkLog()
{
...
LAST_LOG=`ls -tr hbuild.log* | tail -1`
if [ $LAST_LOG = ""]
then
echo hbuild file is not present
exit 1
fi
$1
....
}

grepErr=`echo "grep -i -e ' error ' -e ' errors ' -e 'rror(s)' -e 'Unsatisfied ' -e 'Undefined symbol' -e 'No rule ' -e 'Cannot' -e 'rror:' -e 'Could not find ' -e 'No such file or directory' -e 'Unexpected end of file' -e ' Stop.' -e 'unexpected symbol' -e 'is not a member of'" '$LAST_LOG' "| grep -v 'Warning' > /dev/null"`
....
BUILD_RESULT=`checkLog "$grepErr"`
....


Hope it was more clear this time