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Adding Two Decimals Together and Storing as a Variable

 
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# 1  
Old 04-23-2009
Adding Two Decimals Together and Storing as a Variable
Hello,

I'm writing a shell script which CATs a input file and subsequently runs an executable. Within each do-loop iteration the input file is changed.

Here is where I'm running into trouble....

Lets say I want to add two decimals together: 1.25 + A
A is a decimal with a range between 0...2. It is incremented by 0.05 for each loop. I want to store 1.25 + A as a variable lets say N.
N=$(echo |awk '{ 1.25 + A}') does not do the job. Is it possible to store
1.25 + A as a variable? Thanks for any help.


modey3
# 2  
Old 04-23-2009
Code:
$ echo $0
/bin/ksh
$ A=.25
$ B=$(echo "1.25+$A"|bc)
$ echo $B
1.50

OR
Code:
$ echo $0
/bin/ksh
$ A=.25
$ B=$(nawk -v myA="${A}" 'BEGIN{ print 1.25 + myA}') 
$ echo $B
1.5

Last edited by vgersh99; 04-23-2009 at 06:47 PM.. Reason: changed to '-v'
# 3  
Old 04-23-2009
vgersh99,

Thanks it worked! I tried
B= (echo "1.25+$A"|bc)
Little did I know a $ needed to be added.

modey3
 
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