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counting in unix

 
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# 1  
Old 04-15-2009
counting in unix
my script:
count=0while test $count -lt 10do#do something for 0,1,2...9 count=$(($count+1))doneIt doesnt work. Can anyone tell me what im doing wrong?? thanks
# 2  
Old 04-15-2009
Please use indentation in your code and use code tags.
To do this, select the code with the mouse and click on # above the edit box.

Regards
# 3  
Old 04-15-2009
Code:
count=0
while test $count -lt 10
do
#do something for 0,1,2...9
  count=$(($count+1))
done

Last edited by Franklin52; 04-15-2009 at 02:27 PM.. Reason: Code tags
# 4  
Old 04-15-2009
Dont use $count. use only count like
count=$((count + 1)).
# 5  
Old 04-15-2009
Hi,
What is it that doesn't work? What did You expect it to do?
If i do
Code:
count=0
while test $count -lt 10
do
echo $count
count=$(($count+1))
done

i get
Code:
0
1
2
3

and so on. It works. The comment "#do something for 0,1,2...9" doesn't actually do anything so what You have is loop that start and finishes...

/Lakris

EDIT: Sorry forgot to mention that I use bash but I tried in ksh as well and it works the same.
# 6  
Old 04-15-2009
i get a blank screen
# 7  
Old 04-15-2009
Ok, so I ask again, what did You expect it to do?
It is a loop that counts from 0 to 9 but it doesn't actually do anything, You haven't done any visible actions based on, for example, the count. So it shouldn't show anything.
Have You tried my modified code? Maybe that can give You an idea?

/Lakris
 
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