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Setting the CPUTYPE compiler variable

 
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# 1  
Old 04-05-2009
Setting the CPUTYPE compiler variable
I have a piece of code in BSD that sets a compiler variable, but I am unable to make it work:
Code:
# set compiler options and make options
cputype=`uname -p`
if [ $cputype == "amd64" ]; then
	$cputype="athlon64"
fi

cd /etc
echo " " >> make.conf
echo "CPUTYPE?=$cputype" >> make.conf

The error appears at the comparison operator "==". What do I change to make this work? Thanks in advance.
# 2  
Old 04-05-2009
Code:
cputype=`uname -p`
if [ $cputype == "amd64" ]; then
	$cputype="athlon64"
fi

For starters, Best Practices(Tm) suggest you "should" use ALL_CAPS for customized variables. This keeps convention between customized variables and standard variables (i.e., $PATH, $SHELL, etc).

The 'if' command (to the best of my knowledge) does not recognize "==" as "equal to" -- you want to use "-eq" (or -ne for "not equal to").

Regards.
Last edited by glen.barber; 04-05-2009 at 08:48 AM.. Reason: Fixed formatting
# 3  
Old 04-05-2009
Thank you for your response. The comparison operator for strings is one or more "=" signs, see here: Comparison operators (binary), and it is "-eq" for numbers only.
I currently have the, which seems to work:
Code:
# set compiler options and make options
cputype=`uname -p`
if [ $cputype=="amd64" ]; then
	cputype=athlon64
fi
cd /etc
echo " " >> make.conf
echo "CPUTYPE?=$cputype" >> make.conf

Changes made include the removal of spaces and the removal of the dollar sign in front of the variable.
 
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