UNIX for Dummies Questions & Answers

I have a pipe delimited file with a new record on each line.
A|B|C|D|E
1|||39|40
2|40|||40
3||10|9|

if i search for '1' i want to print the header and the value for each of record.
example if i write a script like myscript.sh with 1 as argument it should search for '1' in first field and then print the following output
A=1
B=
C=
D=39
D=40

how can i do that? just a few commands and pointers will help..

thanks,
Niks

Set IFS to the pipe character for the read command, then start tailing the file on line two to bypass the text field of A|B|C|D|E, then check variable A to see if it is set to 1 and if it is print all the variables for that line.

Code:

IFS="|"
tail +2 input_file | while read A B C D E; do
  if [ $A -eq 1 ]; then
    echo "
A=$A
B=$B
C=$C
D=$D
E=$E
    "
  fi
done

Code:

printf "Read Variable: "
read var

nawk -F\| -v X=$var '
{ if ( NR == 1 )
        { for ( i=1; i<=NF; i++ )
         H[i]=$i
         HNF=NF }
}
{ if ( $1 == X )
        { print $0; for ( i=1; i<=HNF; i++ ) print H[i]"="$i }
}
' FILE

ldapswandog/pmm,

thanks for the quick responses