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capturing exit status ($?) in subshell ??

 
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# 1  
Old 06-04-2003
capturing exit status ($?) in subshell ??
I am trying to capture the exit status of a parent shell
in a subshell.
I am using the trap .. Exit command in the subshell
I cant use the export command in the parent shell to
to export a variable with the exit status to the subshell.
I would have tooooo many parent shells to change.


Parent Shell
. /subshell #Include sub shell
Code code ....
exit 1

End of Parent Shell

subshell

'trap echo $? ' EXIT

#End subshell

My problem is the echo command displays 0.

Any ideas would be greatllllly appreciatedSmilie
# 2  
Old 06-04-2003
Re: capturing exit status ($?) in subshell ??
Quote:
Originally posted by Bob Bannon
I am trying to capture the exit status of a parent shell
in a subshell.
I am using the trap .. Exit command in the subshell
I cant use the export command in the parent shell to
to export a variable with the exit status to the subshell.
I would have tooooo many parent shells to change.


Parent Shell
. /subshell #Include sub shell
Code code ....
exit 1

End of Parent Shell

subshell

'trap echo $? ' EXIT

#End subshell

My problem is the echo command displays 0.

Any ideas would be greatllllly appreciatedSmilie
The way you have this written, your subshell is going to execute until it completes before passing control back to your parent. Given that, your parent shouldnt fail before your child. It would be the other way around.
Last edited by google; 06-04-2003 at 06:25 PM..
# 3  
Old 06-04-2003
What you are calling a subshell isn't one and you seem to have parent and child mixed up.

If you write a command and call it "subshell". you can run it and get the exit code like this..

./subshell
exitcode=$?

And it doesn't matter that "subshell" is command that is also a shell script.
 
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