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'Crop' date from filename into a variable

 
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# 1  
Old 02-26-2009
'Crop' date from filename into a variable
Hi all,

I have a scenario as below. I created a file -

$touch myfile.onlytesting.20090227.txt

I want to assign the date only - 20090227 into a variable x.

How do I do this in unix command?

Please help. ThanksSmilie
# 2  
Old 02-26-2009
how about this:
Code:
d=$(date +"%Y%m%d")
touch myfile.onlytest.$d.txt

# 3  
Old 02-26-2009
If you are willing to extract the datefield enclosed in the file name, here is a solution:
Code:
ant:/home/vbe $ echo myfile.onlytesting.20090227.txt|awk -F\. '{print $(NF-1)}'
20090227

I suppose my other mates will give you a sed version very shortly...
# 4  
Old 02-26-2009
Quote:
Originally Posted by vbe
If you are willing to extract the datefield enclosed in the file name, here is a solution:
Code:
ant:/home/vbe $ echo myfile.onlytesting.20090227.txt|awk -F\. '{print $(NF-1)}'
20090227

I suppose my other mates will give you a sed version very shortly...

Hi.. this is working but what if my filename is below :
myfile.onlytesting.200902270000.txt

but I only want 20090227 to be extracted.. and omit the 0000. How do I do this? Thanks again Smilie
# 5  
Old 02-26-2009
step by step
There are many ways one of them..u can pipe it..this is for explanation...instead of awk you can use cut as well

Code:
 > x=myfile.onlytesting.20090227.txt
 > y=`basename $x .txt`
 > echo $y
myfile.onlytesting.20090227
> echo $y|nawk '{print substr($0,length-7)}'
20090227

 
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