I am trying to write a shell script for the following requirement .
In the directory TEST there are following set of files
a_79cdcd9c8_200809.txt
a_*_200808.txt
a_*_200807.txt
b...
c...
d....
e...
f...
g....
Need to read the ones starting with a -e (These are not the actual starting strings).So goal is to read and process all the files for that quarter.All files starting with {a -e ] and ending with 200809,200809,200807 followed by .txt need to be processed one at a time.
I am not able to figure out the problem
Code:
#!/bin/ksh
#Array
set -A files -- a b c d e
YEAR=2008
Month=09
for LINE in "${files[@]}";
do
echo $LINE
COUNT=1
typeset -xZ2 Mth=$Mon
echo $Mth
while [ $COUNT -lt 4 ];
do
echo "$TEST/$LINE"_*"$YEAR$Mth".txt
ls -1 "$TEST/$LINE"_*"$YEAR$Mth".txt|while read obj # I think this is the # place where the error lies. It should loop twice if there are two files #with this pattern
do
echo "Inside DO loop"
LINE=`basename $obj .txt`
#do something
done
Mth=`expr $Mth - 1` # Reduce the count of month to read the files for #next month
COUNT=`expr $COUNT + 1`# Count controls the execution just for a #quarter and hence loops thrice.
done
done
Your script looks complex...
if you put set -x at the begining of your script, you should see where the error is.
You could also try to redirect result of ls in a text file, and then use the file with the while loop.
This could show where the probleme is.
to read "a b c d e" files, why not to had a grep "^[abcde]"
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