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cut a variabe value

 
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# 1  
Old 02-25-2009
Java cut a variabe value
Hi All,

My target is to cut a variable value's.
My intput is "arunprasd12345678"
My output should be "12345678"

Operation is: Need to fileter out the last 8 characters of the value of a variable.


Please help me.
# 2  
Old 02-25-2009
Quote:
Originally Posted by Arunprasad
Hi All,

My target is to cut a variable value's.
My intput is "arunprasd12345678"
My output should be "12345678"

Operation is: Need to fileter out the last 8 characters of the value of a variable.


Please help me.
Try a regular expression to strip out everything but the digits.
# 3  
Old 02-25-2009
Java
Thanks,
but my aim is to take last 8 digits of that variable.
not to split characters and integers.

Please help me out.
# 4  
Old 02-25-2009
To print from the first digit:

Code:
sed 's/[^0-9]*\(.*\)/\1/'

To print the last 8 position:

Code:
awk '{print substr($0,length-7)}'

Regards
# 5  
Old 02-25-2009
Try this :

Code:
var="arunprasd12345678"
echo ${var#"${var%????????}"}

# 6  
Old 02-26-2009
Code:
[rick ~]$ x=abcdef12345678
[rick ~]$ l=${#x}
[rick ~]$ echo $x | cut -c$(($l - 7))-
12345678
[rick ~]$

Last edited by rmoncello; 02-26-2009 at 03:21 PM..
 
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