UNIX for Dummies Questions & Answers

Hi all,

I have this scenario where:-



The file that I want to save its name into array df[1] is my.08120323.trx which is located in the dir as below:

$ pwd

/u01/abc/def/SRC_datafiles

$ ls *trx

my.08120323.trx

$ df[1]=*"trx" ##keeping the filename my.08120323.trx into df[1]

$ echo ${df[1]}

my.08120323.trx ##getting the correct full output



I want $df[1] content - my.08120323.trx to be maintained in any directory that I go.. example below directory.. but I only got *trx value as below when I echo ${df[1]}

$ cd ../..

$ pwd

/u01/abc

$ echo ${df[1]}

*trx ##this is not the output that i expected.. i want it to show my.08120323.trx

$



How do I maintain the value of df[1] to be my.08120323.trx instead of only *trx in any directory I go?

Please shed some light.

Thanks!

Code:

$ df[1]=$( echo *trx ) ##keeping the filename my.08120323.trx into df[1]

$ echo ${df[1]}

The problem is the parsing sequence of the shell.

Variable assignment occurs before file metacharacter expansion.

In both cases, the value of df[1] is actually only *trx.
When there is a file that matches that pattern,
the shell expands to show the matching files.