awk and next


 
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# 1  
Old 02-23-2009
awk and next

Hi,
I am having trouble with awk. I need to read in the first line and only keep it if the next x number of lines doesnt contain 9999 in it.

This example is a file I want to get rid of.
Code:
start     -73.38300     40.10000    1988       1      30       9    5566
      1.00000      4.91100   9999.00000
      5.30000      3.81100   9999.00000
     10.50000      4.23100   9999.00000
     15.80000      4.40000   9999.00000
     21.10000      3.67500   9999.00000
     26.40000      5.18800   9999.00000
     31.60000      3.14600   9999.00000
     39.00000      3.87500   9999.00000
     39.10000      3.73300   9999.00000

This is an example of things I would like to keep
Code:
start     -73.60000     40.26700    1988       1      30       6    5564
      1.00000      3.68000     31.66500
      5.00000      3.67000     31.66900
     10.00000      3.68000     31.65000
     15.00000      3.68000     31.64800
     20.00000      3.68000     31.64700
     21.00000      3.68000     31.64700
start     -73.08300     39.86700    1988       1      30      14    5568
      1.00000      6.10000     32.80200
      5.00000      6.10000     32.80100
     10.00000      6.10000     32.79200
     15.00000      6.10000     32.78900
     20.00000      6.10000     32.78900
     25.00000      6.11000     32.79000
     30.00000      6.10000     32.78900
     35.00000      6.10000     32.78900
     40.00000      6.10000     32.78900
     45.00000      6.10000     32.78800
     50.00000      6.11000     32.79000
     55.00000      6.11000     32.79000
     60.00000      6.11000     32.79300
     63.00000      6.11000     32.79200

The output should be the same as the input. I was trying to use NEXT but I cant seem to get it to work.
I hope thats clear
Thanks for any suggestions
# 2  
Old 02-24-2009
Not sure what you exactly want; you can try this though in case it brings the desired output; I pasted your examples together to one file and added some more of those ranges with 9999.

Code:
grep -v 9999 infile| awk '/^s/ {l=$0; next} !/9999/ {print l; print; l="" }'| grep -v ^$

 
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