UNIX for Dummies Questions & Answers

@Whiteboard

he write:

"First I match the first column I find intersection (A,C, E), then I want to take those lines with ACE out from yyy.txt"

oops... sorry.. then the solution given by you and vgersh99 will work fine...

Code:

 
nawk 'FNR==NR {a[$0]++; next} a[$0]' xxx.txt yyy.txt

Code:

 
nawk 'FNR==NR {a[$0]++; next} a[$0]' xxx.txt yyy.txt

@vgersh99

Can you pls explain ur code....

use 'awk' instead of 'nawk'.

I´m tried do something very similar
list A
1
List B
1 2 3
And want list C with intersection of A and B by column 1
with
1 2 3
as answer

I tried
B=ListOfProcess=$(ps -ef | grep sappp | awk '{print $1,$2,$6}' | perl -lne 'print unless /root/ | /user1/ | /user2/ | /user3/ | /user4/' | sort)


A=ListToKill= $(who -u | sort +5 |awk '{print $1,$6,$2}' | perl -lne 'print unless /root/ | /user1/ | /user2/ | /user3/ | /user4/ | /0:/' |awk '{print $3}' |sort)

awk 'FNR==NR {a[$0]++; next} !a[$0]' A B

But did´t work, its giving the total instead the intersection only.

A link for other topic is enough, I can try understand other examples just didnt find yet.
Thanks