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awk match pattern and print lines till next blank line

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# 1  
Old 04-21-2020
awk match pattern and print lines till next blank line
Dear Experts,




Here is my input files which has various sections of data.


Code:
 SURVEY RESULT

NUMADDR             NUB       NUBA
4-9XXXXXXXXXXX      1244359    1099510
4-9YYYYYYYYYYY           692        586
4-2XXXXXXXXXXX           223        147
4-8YYYYYYYYYYY            1          1

SUMADDR             NUB       NUBA
4-9XXXXXXXXXXX      1244359    1099510
4-9YYYYYYYYYYY           692        586
4-2XXXXXXXXXXX           223        147
4-8YYYYYYYYYYY            1          1


TOTNSUB                NUB       NUBA
4-9XXXXXXXXXXX      128888    1099510
4-9YYYYYYYYYYY           692        586
4-2XXXXXXXXXXX           223        147
4-8YYYYYYYYYYY            1          1

TOTNSUBA             NUB       NUBA
4-9XXXXXXXXXXX      129999    1099510
4-9YYYYYYYYYYY           692        586
4-2XXXXXXXXXXX           223        147
4-8YYYYYYYYYYY            1          1


The below awk command to get data matching first column NUMADDR till number of lines specified in command.
I need only change here is instead of mentioning static number of lines for (y=0;y>4;y++) need all lines till next blank line.


Code:
 awk '{a[++i]=$0;}END{for (j=1;j<NR;j++) {if (a[j]~"NUMADDR") {for (y=0;y>5;y++) print a[j+y]}}}' file


Output should be as below


Code:
NUMADDR             NUB       NUBA
4-9XXXXXXXXXXX      1244359    1099510
4-9YYYYYYYYYYY           692        586
4-2XXXXXXXXXXX           223        147
4-8YYYYYYYYYYY            1          1

# 2  
Old 04-21-2020
Dear experts,




Here below i tried and its worked


Code:
$ awk '$0~s{p=1;next}/^$/{p=0}p' s="NUMADDR" mgsvp_test.txt
4-9XXXXXXXXXXX      1244359    1099510
4-9YYYYYYYYYYY           692        586
4-2XXXXXXXXXXX           223        147
4-8YYYYYYYYYYY            1          1

eshaqur@SA-00001256 ~
$ awk '$0~s{p=1;next}/^$/{p=0}p' s="SUMADDR" mgsvp_test.txt
4-9XXXXXXXXXXX      1244359    1099510
4-9YYYYYYYYYYY           692        586
4-2XXXXXXXXXXX           223        147
4-8YYYYYYYYYYY            1          1

# 3  
Old 04-21-2020
awk can do this during reading the input file - no need to store everything and process in the END section.
Code:
awk '$1~search {p=1} NF==0 {p=0}; p' search="NUMADDR" file

The p variable controls when to be printed. The bare p seclector without a following { action } defaults to { print }.

EDIT: Just seeing your previous post. It is quite similar to my solution.
This User Gave Thanks to MadeInGermany For This Post:
shanul karim
# 4  
Old 04-21-2020
G8 thanks a lot


its working and good enough


Code:
awk '$1~search {p=1} NF==0 {p=0}; p' search="NUMADDR" mgsvp_test.txt
NUMADDR             NSUB       NSUBA
4-9XXXXXXXXXXX      1244359    1099510
4-9YYYYYYYYYYY           692        586
4-2XXXXXXXXXXX           223        147
4-8YYYYYYYYYYY            1          1

# 5  
Old 04-21-2020
How about
Code:
awk '/SUMADDR/,/^$/ ' file

or
Code:
sed -n '/SUMADDR/,/^$/p ' file

?
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