Script to list Sequential files


 
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# 1  
Old 04-21-2020
Script to list Sequential files

I have sequential files like this. I'm trying to write a bash shell script to list all of them. These files are part of mysql to do database point in time recovery

Code:
bin.000001
.
.
.
bin.000999


I have something like this but it won't display bin.000010 and up. If anyone has a solution pls do let me know.
Code:
# find ~/ -name 'bin.00000[0-99]


Last edited by vbe; 04-21-2020 at 04:36 AM..
# 2  
Old 04-21-2020
Each character set [ ] matches one character
Code:
find ~/ -name 'bin.000[0-9][0-9][0-9]'


Last edited by MadeInGermany; 04-21-2020 at 07:04 PM.. Reason: Rephrased
# 3  
Old 04-21-2020
Thanks madelngermany,

I used find ~/ -name 'bin.0000[01-9][10-999]' and it worked.

Can you explain what is [01-9][10-999]?
# 4  
Old 04-21-2020
A bit difficult to believe your pattern matched bin.000999 as it is for the last two digits only, one per square bracket pattern. First pattern will match 0 and 1-9, second 1, 0-9, 9, and 9 (some redundancy, i'd say).
# 5  
Old 04-21-2020
Quote:
Originally Posted by RudiC
A bit difficult to believe your pattern matched bin.000999 as it is for the last two digits only, one per square bracket pattern. First pattern will match 0 and 1-9, second 1, 0-9, 9, and 9 (some redundancy, i'd say).
Sorry, I made a mistake, my code did not work and i used your code it's working.
Can you explain what is [0-9][0-9][0-9]
# 6  
Old 04-21-2020
man bash:
Quote:
Pathname Expansion
Pattern Matching


Any character that appears in a pattern, other than the special pattern characters described below, matches itself.
.
.
.
[...] Matches any one of the enclosed characters. A pair of characters separated by a hyphen denotes a range expression; any character
that falls between those two characters, inclusive, using the current locale's collating sequence and character set, is matched.
So one [0-9] means one character from (the range) 0 through 9.
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