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# 1  
Old 01-04-2020
Pass config file to bash script

I just want to make sure I am understanding how to pass a config file to a bash script . In the below I pass to arguments to a script, then define them in the script as id and config. I then source config using ., if I understand correctly the variables in the config file can now be used by the script? Thank you Smilie.



Code:
bash /path/to/script.sh <arg1> <arg2>


Code:
arg1=id
arg2=config

contents of config


Code:
# COMMENT Line
var1=/path/to/file
# COMMENT Line
var2=/path/to/file

Code:
script.sh
#!/bin/bash


# define arg

id=$1  

config=$2 


source config for script to use

. $config

# 2  
Old 01-05-2020
Hi
Try to find out
Code:
mkdir TEST && cd $_
echo -e '. $1\necho $var' >script.sh
echo 'var=yes' >config
bash script.sh config
yes


Last edited by nezabudka; 01-05-2020 at 09:20 AM..
This User Gave Thanks to nezabudka For This Post:
# 3  
Old 01-05-2020
I get: y being echo on a newline. Thankk you Smilie.


Code:
mkdir TEST && cd $_
echo -e '. $1\necho var' >script.sh
echo 'var=yes' >config
bash script.sh config
yes

Code:
y
y
y

should script.sh look like:

Code:
$1=config  # define argument

. $config   # source config file in script

echo "$@"  # read contents of config using posistional parameters
echo -e  $1 # echo each line in script


Last edited by cmccabe; 01-05-2020 at 09:51 AM.. Reason: added comments
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# 4  
Old 01-05-2020
I made a mistake in the expression echo -e '. $1\necho var' >script.sh
I fixed it and you probably just copied it before that Smilie
It will be right echo -e '. $1\necho $var' >script.sh

--- Post updated at 17:15 ---

Quote:
Originally Posted by cmccabe

should script.sh look like:

Code:
$1=config  # define argument

. $config   # source config file in script

echo "$@"  # read contents of config using posistional parameters
echo -e  $1 # echo each line in script

if this line is from script then it is not correct $1=config # define argument
positional parameters are defined as
Code:
config=file.txt
next=elsefile.txt
set -- $config $next
echo $1 $2
file.txt elsefile.txt

Or did you mean that when starting a script, the first parameter is defined $1 == config

Last edited by nezabudka; 01-05-2020 at 10:25 AM..
This User Gave Thanks to nezabudka For This Post:
# 5  
Old 01-05-2020
The first parameter starting the script is config, there are two possible choices depending on the data type so I am going to pass it as an argument. Thank you Smilie.

Code:
config=$1

set -- $config
echo -e "$@"

but this echos the path to config, I need each line in the config avaliable to the script to use. Do I need to source config? Thank you.

I think this will work:
Code:
config=$1

set -- $config
echo -e "$@"
while read line; do
  echo "$line" >script.sh
done <"$config"

I think now each line in config can be used in [/ICODE]script.sh[/ICODE].

Last edited by cmccabe; 01-05-2020 at 11:37 AM.. Reason: fixed format, added details
# 6  
Old 01-05-2020
In the script, it is better to immediately indicate the path to the file.
Code:
. /path/to/config

You can also add a default value if a file is not specified at startup
Code:
. ${1:-/path/to/config}

--- Post updated at 18:48 ---

for example
Code:
mkdir TEST && cd $_
echo var=one >config
echo var=two >$HOME/else_config

cat script.sh
Code:
. ${1:-$HOME/else_config}
echo $var

launch
Code:
bash script config
one
bash script
two

This User Gave Thanks to nezabudka For This Post:
# 7  
Old 01-05-2020
if I just print the $line I do see each var printed. However when I re-direct it to the script I do not see them. Are they avaliable to the script to use?

the config file will be different for data type 1 then for data type 2.

For data type 1 the config file will be /path/to/config1 and for data type 2 [ICODE]/path/to/config2[/ICODE, so the /path/to is always the same but the config file may be different. Can

Code:
. $config

be used to immediatly source the config file being passed by the argument? Thank you Smilie.

Last edited by cmccabe; 01-05-2020 at 11:55 AM.. Reason: fixed format

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