Quick and dirty - do not use with file names with space or other special characters!
This gives the file names. You can use xargs to convert stdin to command arguments
In the last grep use -l or -h option to only print file names or contents.
This User Gave Thanks to MadeInGermany For This Post:
You might be better to crete two temporary reference files with the correct timestamp.
What criteria do you have for the search date(s)? If it is just today's files, then you could do something like:
This will create you a marker file based on the current date, setting it to midnight (the 0000 at the end of the date command) Using that, you can find any files that are newer and search for them. For each file found, it then runs the grep with {} representing the file just found. The reason to add /dev/null to the end is so that grep sees two files and therefore prints the file names where it finds your string.
Does this help? You may need to add in a -maxdepth flag to suit your needs if there are subdirectories.
If you have a date range to collect files from or a particular day to search, you can create two reference files to mark the start and end of the range. You would then add a ! -newer "${second_ref_file}" to stop it finding anything that is too new.
Of course, this could be modified to set specific times by replacing the 0000 with a required time coding when touching a reference file if that is required, e.g. you just want a particular hour.
i have this line of code that looks for the same file if it is currently running and returns the count.
`ps -eaf -o args | grep -i sfs_pcard_load_file.ksh | grep -v grep | wc -l`
basically it is assigned to a variable
ISRUNNING=`ps -eaf -o args | grep -i sfs_pcard_load_file.ksh |... (6 Replies)
Hi,
I have a number of files containing the information below.
"""""
Fundallinfo
6.3950 14.9715 14.0482
"""""
I would like to grep for Fundallinfo and use it to read the next line? I ideally would like to read the three numbers that follow in the next line and... (2 Replies)
Hello.
I want to get all modules which are loaded and which name are exactly 2 characters long and not more than 2 characters and begin with "nv"
lsmod | (e)grep '^nv????????????
I want to get all modules which are loaded and which name begin with "nv" and are 2 to 7 characters long
... (1 Reply)
I have a directory I need to grep which consists of numbered sub directories. The sub directory names change daily. A file resides in this main directory that shows which sub directories are FULL backups or INCREMENTAL backups.
My goal is to grep the directory for the word "full" and then... (2 Replies)
Hi All,
Please i need to know the difference between grep, egrep & grep -i when used to serach through a file.
My platform is SunOS 5.9 & i'm using the korn shell.
Regards,
- divroro12 - (2 Replies)
Hi All, I need to grep few files which has words like the below in the file name , which i want to put it in a file and and grep for the files which contain these names and move it to a new directory ,
full file name -C20091210.1000-20091210.1100_SMGBSC3:1000... (2 Replies)
Hello,
I'm working on unix with grep (GNU grep) 2.5.1. I'm going through some of the newer regex syntax using Regular Expression Reference - Advanced Syntax a guide.
ls -aLl /bin | grep "\(x\)"
Which works, just highlights 'x' where ever, when ever.
I'm trying to to get (?:) to work but... (4 Replies)
Hello,
I looking to use grep to return a string with exactly n matches.
I'm building off this:
ls -aLl /bin | grep '^.\{9\}x' | tr -s ' '
-rwxr-xr-x 1 root root 632816 Nov 25 2008 vi
-rwxr-xr-x 1 root root 632816 Nov 25 2008 view
-rwxr-xr-x 1 root root 16008 May 25 2008... (7 Replies)
Hi Guys,
I need to set the value of $7 to zero in case $7 is NULL. I've tried the below command but doesn't work. Any ideas. thanks guys.
MEM=`ps v $PPID| grep -i db2 | grep -v grep| awk '{ if ( $7 ~ " " ) { print 0 } else { print $7}}' `
Harby. (4 Replies)