Bash Script


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# 1  
Bash Script

Code: File is read in from wrapper and declared file_name


Code:
IFS=","
sed 1d $file_name | while read Name Job Age Title
 
 
do
count=0
   dirname=$Name
   while [ -d "$dirname" ]
   do
       ((count++))
       dirname="${Name}$count"
   done
 
   echo "=================="
   echo "Name: $Name"
   echo "Job: $Job"
   echo "Age: $Age"
   echo "Title: $Title"
   echo "==================="
 
done  <$file_name



When script is run(first two outputs, actually outputs everythin stoed in the variable but its just to show the issue at the top )
Code:
==================
Name: Name
Job: Job
Age: Age
Title: Title
===================
==================
Name: James
Job: Fireman
Age: 22
Title: Mr
===================
==================

so csv file looks like this

Code:
Name,Job,Age,Title
James,Fireman,22,Mr
etc,etc,etc,etc

When read into the file i want the header not to be read so when it's printed to the screen it doesn't output Name: Name. Should look like of Name: (Then a real user name like James)

Moderator's Comments:
Mod Comment Please do wrap your samples always in CODE TAGS as per forum rules.

Last edited by RavinderSingh13; 11-30-2019 at 12:03 AM..
# 2  
You are using two stdin feeds to the while loop:
Code:
sed 1d $file_name |

and
Code:
<$file_name

If you leave the latter it should skip the first line because of the sed statement...
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