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How to split one long column into multiple rows with 3 each ?

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# 1  
Old 11-21-2019
How to split one long column into multiple rows with 3 each ?
I have a large csv dataset like this :
Code:
A	value1
A	value2
A	value3
B	value1
B	value2
B	value3
C	value1
C	value2
C	value3

what I expected output is :
Code:
A	value1	value2	value3
B	value1	value2	value3
C	value1	value2	value3

I'm thinking of use like awk, columns , but haven't find a proper way to do that.
could anyone give me some clues?
# 2  
Old 11-21-2019
Try
Code:
awk 'LAST != $1 {printf "%s%s", DL, $0; LAST = $1; DL = RS; next}; {printf "\t%s", $2} END {printf RS}' file
A    value1    value2    value3
B    value1    value2    value3
C    value1    value2    value3

This User Gave Thanks to RudiC For This Post:
nengcheng
# 3  
Old 11-22-2019
Thank you RudiC . That's a cool solution, which is also suitable for more complex situations.
# 4  
Old 02-26-2020
Nice solution Smilie
For symmetry reason (and the border case "empty input file") it should be END {printf DL}.
This User Gave Thanks to MadeInGermany For This Post:
RudiC
# 5  
Old 02-26-2020
Hi.

I've often wondered why there hasn't been a utility (or mode in join) to do this kind of operation -- a self-join, as it were ... cheers, drl
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