How to convert dec to hex in python?


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# 1  
How to convert dec to hex in python?

When I try to convert big numbers I get extra numbers at the end that doesn't move plus an L character too. How to remove the 4 extra characters at the end 000L?

8b8dbbc584d9c000L

8b8dc4ddd34c6000L

8b8dcdf621bf0000L

8b8dd70e7031a000L

8b8de026bea44000L






Code:
#!/usr/bin/python

    import sys

    def int_tuple_from_cmdline():
      """return exactly two integers form sys.argv
         or die with an error message
      """
      import sys
      args = sys.argv[1:] # drop first entry (progpath)
      if len(args) != 2:
          raise SystemExit("\n#################################################\n# Please enter both a 
    start and stop parameter. #\n#################################################")
      for i in range(len(args)):
          try:
             args[i] = int(args[i])
          except ValueError:
             raise SystemExit("\n#################################################\n# Parameter %d is not an integer. You entered: %s #\n#################################################\n" %(i+1,args[i]))
      return tuple(args)

    start, stop = int_tuple_from_cmdline()

    r = start - 10000000000000
    while r < stop:
	r = r + 50000000000000
	hx = hex(r)[2:]
	print(hx)


Last edited by bigvito19; 10-13-2019 at 02:57 PM..
# 2  
Are you sure the zeros are not required because the middle one of the hex' values has 4 of them and the 'L' stands for LONG?
Also, as a guess, you must be using Python Version 2.x.x possibly 2.7.x and not 3.x.x.

So could you confirm your Python Version and OS it is running on...

I am guessing that your decimal number was:
Code:
>>> int(0x8b8dbbc584d9c000L)
10055900000000000000L
>>> hex(10055900000000000000L)
'0x8b8dbbc584d9c000L'
>>> _


Last edited by wisecracker; 10-13-2019 at 03:06 PM.. Reason: Add code block.
# 3  
Quote:
Originally Posted by wisecracker
Are you sure the zeros are not required because the middle one of the hex' values has 4 of them and the 'L' stands for LONG?
Also, as a guess, you must be using Python Version 2.x.x possibly 2.7.x and not 3.x.x.



So could you confirm your Python Version and OS it is running on...
Yes I'm using python.2.7 on Ubuntu and Centos
# 4  
I edited my previous post to show you, and you do not need to remove the 'L' as conversion to either format is unaffected by the letter.

It also looks as though the zeros ARE required so if it necessary to remove the 'L' then let us know...

Bazza...
# 5  
Quote:
Originally Posted by wisecracker
I edited my previous post to show you, and you do not need to remove the 'L' as conversion to either format is unaffected by the letter.

It also looks as though the zeros ARE required so if it necessary to remove the 'L' then let us know...

Bazza...
Yes I want the extra characters to be remove because I'm running this script against another script. It needs to be on hex form.
# 6  
Try:
Code:
hx = hex(r)[2:][:-1]

To remove the 'L'. You remove the zeros at your own risk...
# 7  
Quote:
Originally Posted by wisecracker
Try:
Code:
hx = hex(r)[2:][:-1]

To remove the 'L'. You remove the zeros at your own risk...
Thanks that did remove the L.

Last edited by bigvito19; 10-13-2019 at 04:05 PM..
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