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# 1  
Hide output of a certain file on print

Im trying to print /etc/passwd with a variable connecting to /etc group/
But when im trying to print the output, /etc/group is printing also. Can i ask for help on what command to use
so it will ignore /etc/group and only print /etc/passwd.

here's the sample script. pages number and the /10 entry line pages should be used also.

Code:
 awk -F":" -v A=$(wc -l < /etc/passwd) '
    BEGIN   {
            NUM_PAGES=A/10+1
            print "--------------------------------------------------"
            printf "%-20s %-20s %-3s\n","USERNAME","GUID","DIRECTORY"
            print "--------------------------------------------------"
            }

   !(NR%10) {
             PAGE++
             printf "--- Page %d of %d ---",PAGE,NUM_PAGES
             getline rc < "-"; system("tput cuu1")
            }

   (NR==FNR){
            B[$3]=$1
            next } $4 in B { $4=B[$4]
            }


            { printf "%-20s %-20s %-3s\n", $1, $4, $7 }

' /etc/group /etc/passwd

# 2  
Just reverse the order of the statements, i.e. have the file1 processing (NR==FNR) before the page processing !(NR%10). And, use FNR for the latter.


Be aware that careful indenting (as shown by Scrutinizer in your other thread) helps others (and you!) to easily read and understand your code.
This User Gave Thanks to RudiC For This Post:
# 3  
Thank you Sir!
Will have to study a lot more.
Have a magnificent day.

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