Ksh: How to get name of script when in same script


 
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# 1  
Old 05-22-2019
Ksh: How to get name of script when in same script

To get the script name the variable $0 can normally be used.
Problem happens when the command is started with a "dot space" as in: . myscript.sh.
$0 shows -ksh not myscript.sh
From within the script ps -f does not show myscript.sh either.
Someone suggested using readlink but cannot get that to work

Here is a test script:
Code:
#myscript.sh
echo myscript=$0
mypid=$$
echo mypid=$mypid
ps -f
ls /proc/$mypid/exe
readlink /proc/$mypid/exe

Code:
uname -a
Linux svappd02 2.6.32-754.11.1.el6.x86_64 #1 SMP Tue Jan 22 17:25:23 EST 2019 x86_64 x86_64 x86_64 GNU/Linux

Thanks!

Last edited by Don Cragun; 05-22-2019 at 05:42 PM.. Reason: Add CODE and ICODE tags.
# 2  
Old 05-22-2019
Quote:
Originally Posted by Michael Fitz
To get the script name the variable $0 can normally be used.
Problem happens when the command is started with a "dot space" as in: . myscript.sh.
$0 shows -ksh not myscript.sh
From within the script ps -f does not show myscript.sh either.
Someone suggested using readlink but cannot get that to work

Here is a test script:
Code:
#myscript.sh
echo myscript=$0
mypid=$$
echo mypid=$mypid
ps -f
ls /proc/$mypid/exe
readlink /proc/$mypid/exe

Code:
uname -a
Linux svappd02 2.6.32-754.11.1.el6.x86_64 #1 SMP Tue Jan 22 17:25:23 EST 2019 x86_64 x86_64 x86_64 GNU/Linux

Thanks!
The . command asks the shell to include the text found in the file named by its operand in the body of the currently running script and execute in the current shell execution environment without starting another shell or sub-shell to process the commands found in that file.

If it is important for the file you are running with the . command to accurately specify the name of the file from which . read those commands, the script calling it will need to cooperate with it something like:
Updated calling calling myscript.sh:
Code:
... ... ...
dotscript="my script.sh"
. "$dotscript"
... ... ...

Updated code in myscript.sh:
Code:
#myscript.sh
mypid=$$
echo "The code in $dotscript is being run by $0 with PID $mypid"

# 3  
Old 05-23-2019
Ran new "myscript.sh" still shows "-ksh" not "myscript.sh"
Code:
$ . myscript.sh
The code in  is being run by -ksh with PID 1581

# 4  
Old 05-23-2019
Quote:
Originally Posted by Michael Fitz
Ran new "myscript.sh" still shows "-ksh" not "myscript.sh"
Code:
$ . myscript.sh
The code in  is being run by -ksh with PID 1581

No. It is being run by -ksh as I explained in post #2. What it shows (by the two spaces between "in" and "is" in the output you showed us) is that you didn't set dotscript="myscript.sh" before running the command . myscript.sh as I suggested in post #2.
# 5  
Old 05-23-2019
Don, I guess a better question is how to derive the script name when it's "sourced" WITHOUT hardwiring its name in the script itself.
I've been dealing with the fullpath to the script name using this paradigm in ksh:
Code:
#!/usr/bin/ksh
#set -x

thisFile="$(whence ${0})"
echo "this file->[${thisFile}]"

Obviously it doesn't work when the script is sourced.

I tried this for testing:
Code:
#!/usr/bin/ksh
set -x

echo "\$0 ->[${0}] \$# -> [${#}]"
#thisFile="$(whence ${0})"
if [[ "${0}" = -* ]]; then
   # cannot get this to work when sourced....
   thisFile="${1}"
else
   # bash-ism
   #thisFile="$(type -P ${0})"
   # ksh-ism
   thisFile="$(whence ${0})"
fi

echo "this file->[${thisFile}]"

# 6  
Old 05-23-2019
how about this approach [covering bash/ksh - might need to enhance it for other (zsh/sh/etc)]
Code:
#!/bin/ksh
#set -x

#echo "\$0 ->[${0}] \$# -> [${#}] \$_ -> [${_}] "
case "${0}" in
   -bash) thisFile="${BASH_ARGV[0]}"
          ;;
   *ksh) thisFile="${_}"
          ;;
   *)
      #thisFile="$(type -P ${0})"
      thisFile="$(whence ${0})"
      ;;
esac

echo "this file->[${thisFile}]"

This User Gave Thanks to vgersh99 For This Post:
# 7  
Old 05-24-2019
Only bash provides a method:
Code:
echo "I am $BASH_SOURCE"

With ksh you have to stick to a workaround like Don's suggestion
Code:
dotscript="myscript.sh"; . "$dotscript"

Code:
echo "I am ${dotscript:-$0}"

This User Gave Thanks to MadeInGermany For This Post:
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