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Setting config database user and password using sed

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# 1  
Old 05-13-2019
Setting config database user and password using sed
Hello everybody,

I need to modify 200 files using a patern matching, I would like to do it with sed but it's not working with the following syntax:

Code:
sed -e 's/DATABASE_PASSWORD.*oldpass/DATABASE_PASSWORD__', 'newpass/g' config.php

need to find:
Code:
define("__DATABASE_PASSWORD__",              "oldpass");

and to be replaced by:
Code:
define("__DATABASE_PASSWORD__",              "newpass");

Do you have any idea ?

Thank you for your help.
# 2  
Old 05-13-2019
Maybe just keep it simple?

Code:
sed -i.bak 's/old-text/new-text/g' filename

In your case:

Code:
sed -i.bak  's/oldpass/newpass/g' config.php

This User Gave Thanks to Neo For This Post:
RavinderSingh13
# 3  
Old 05-13-2019
Code:
sed 's%\(define("__DATABASE_PASSWORD__",\s*"\)\([^"]\+\)%\1newpass%g'

I guess that newpass will look like /path/to/dir/file (I was mistaken) than
Code:
sed 's/\(define("__DATABASE_PASSWORD__",\s*"\)\([^"]\+\)/\1newpass/g'

Last edited by nezabudka; 05-13-2019 at 05:51 PM..
# 4  
Old 05-13-2019
Hello,
many thanks for your reply.

@Neo, Unfortunately I can't use this command:

Code:
 sed -i.bak  's/oldpass/newpass/g'

Because I have several settings with the same string ... Smilie

Example:
Code:
define("__DATABASE_USER__",              "oldpass");
define("__DATABASE_PASSWORD__",              "oldpass");

I would like to change only the DATABASE_PASSWORD and do not change the string for DATABASE_USER.

I try to change the following bloc using sed substitution: define("__DATABASE_USER__", "oldpass");

@nezabudka, thank you for your help but your command line do not replace

Code:
define("__DATABASE_PASSWORD__",              "oldpass");

by

Code:
define("__DATABASE_PASSWORD__",              "newpass");

Code:
shell command: sed 's/\(define("__DATABASE_PASSWORD__",\s*"\)\([^"]\+\)/\1newpass/g' config.php

output:
Code:
define("__DATABASE_USER__",              "oldpass");
define("__DATABASE_PASSWORD__",              "oldpass");

Good evening.
# 5  
Old 05-13-2019
Try this one:

Code:
sed -i.bak '/DATABASE_PASSWORD/s/oldpass/newpass/'

# 6  
Old 05-14-2019
Dear stomp,
Thank you very much for your help, it's works very well !!!
# 7  
Old 05-14-2019
Making it a bit more precise, so it would not match e.g. a __DATABASE_PASSWORD_ENABLED__
Code:
sed '/"__DATABASE_PASSWORD__"/ s/oldpass/newpass/'

The alternative is without a selector, instead have the substitution match include the selector:
Code:
sed 's/\("__DATABASE_PASSWORD__".*\)oldpass/\1newpass/'

Everything that matches is substituted, so one must capture in a \(group\) and give it back as \1 in the substitution string.
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