Hi,
My objective is to achieve from HB.txt
into adding a day column by using the first column - date.
So far, I'm in progress to try this,
However, the generated output for the new column is after a breakline.
System Specifications:
macOS High Sierra
Terminal - Bash
Please post your OS, shell, and preferred tools' versions in the future so people in here don't need to guess what system features you have available and which you don't.
Your RS character \r (<CR> = 0x0D = ^M) seems a bit strange a choice as \n (<LF> = 0x0A) is the *nix line terminator. How was that input file produced? And, no attempt was made to get to the desired day-of-week result.
GNU date around, and a shell with "process substitution"? Try
The date utility, the awk utility, and the bash utility on macOS don't behave as the current GNU utility extensions that are referenced elsewhere in this thread, but if you're willing to use ksh instead of bash, you could try:
which, with your sample input file, produces the output:
which seems to be what you want except that this will produce 3 character abbreviations for all days of the week instead of producing "Tues" for Tuesdays as you seem to want. Is this close enough?
This was tested on macOS Mojave version 10.14.3 instead of on macOS High Sierra, but I don't think ksh has changed significantly between these two releases.
Hi have a large spreadsheet which has 4 columns
APM00111803814 server_2 96085 Corp IT Desktop and Apps
APM00111803814 server_2 96085 Corp IT Desktop and Apps
APM00111803814 server_2 96034 Storage Mgmt Team
APM00111803814 server_2 96152 GWP... (6 Replies)
Hi,
i have a flat file namely temp.txt with this data below
ID|name|contact_date
101|Kay|2013-12-26
102|let|2013-12-26
I need to modify the date data in the flat file into MM/DD/YYYY HH24:MI:SS format
let me know the code for this.
Thank you! (5 Replies)
Hi All,
I have file like
“April 10, 2013”,”raj”
“April 29, 2013”,”raj1”
Output :
“2013/04/10”,”raj”
“2013/04/29”,”raj1”
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Could you tell me how to convert the following dates?
If I have m/d/yyyy, I want to have
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In other words, I want a 0 inserted whenever the month or day is a single digit.
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I have below date format in a CSV file. (dd/mm/yyyy)
Ex Input:
9/8/2013
Need to convert it into below format (yyyymmdd ) and redirect to new file.
Ex Output:
20130809
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awk < file1 -F~ '{print $10}'
and it gave blank screen
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HI guys,
I have created a script to read 1 column in a csv file and then place it in text file.
However, when i checked out the text file, it is not in a column format...
Example:
CSV file contains
name,age
aa,11
bb,22
cc,33
After using awk to get first column
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