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Grep for multiple string

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# 8  
Old 02-12-2018
Quote:
find the second last and last word before any full stop and print them separated by a space character
yes this perfect.
sorry im not changing my mind but just trying to get the correct command.
im new here so apologies for any inconvenience caused.
# 9  
Old 02-12-2018
I only can repeat what I said in post#4. Your chances to get reasonable help increase with the amount of carefully gathered details in your spec.
Try
Code:
sed -rn 's/([^ ]* [^ ]*\.)/\n\n\1\n/; T; s/\n$//; s/^.*\n\n//; P; D;' file
d lift.
body lift.
weight loss.

# 10  
Old 02-12-2018
Quote:
find the second last and last word before any full stop and print them separated by a space character
yes this is exactly what i want.
sorry about the confusion and thanks for helping again.

---------- Post updated at 12:26 PM ---------- Previous update was at 12:22 PM ----------

ok checking the command now.
# 11  
Old 02-12-2018
@ahfze .. cause you said firstly in example, word is at first line, then differ it. Sed not works, use grep PCRE regex instead:

Code:
$ echo 'A circumferential abdominoplasty is an extended abdominoplasty plus a d lift. The resulting scar runs all the way around the body, and the operation is also called a Belt Lipectomy or lower body lift. This operation is most appropriate for patients who have undergone massive weight loss.' >string

$ grep -Po -e '(\w+)\s+(\w+\.)' string
d lift.
body lift.
weight loss.

Last edited by abdulbadii; 02-12-2018 at 09:24 PM..
This User Gave Thanks to abdulbadii For This Post:
ahfze
# 12  
Old 02-13-2018
thanks abdulbadii
the grep code you provided works better.
much appreciated
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