UNIX for Beginners Questions & Answers

Comparing your above code to what was shown in post#2, methinks there's something essential missing?

The additional file found is the one you touched just one line above.

And, please post in an adequate forum.

any help will be appreciated

---------- Post updated at 10:56 AM ---------- Previous update was at 06:09 AM ----------

can anyone please help me on this

First of all carefully read the suggestions provided earlier in post 2 & 4 and try it, then let us know if you don't get the expected results.

Thanks for your reply. I tried below code with and without -t but now it is printing any file name. It creating 2 file in dir. (XXCU_DATA_TOP/AP/in/123) with name 1)201708010000 and 2) startfile. but i dont want to create any new file... I wanted to display the name of the files exist on the dir. (XXCU_DATA_TOP/AP/in/123). I am able to display the files from the dir with code2 but i wanted to add the from date paramter so based on parameter i need to display the file names

CODE

Code:

echo "$XXCU_DATA_TOP/AP/in/123"
cd $XXCU_DATA_TOP/AP/in/123

touch  201708010000 startfile
find . -type f -maxdepth 1 -newer startfile -print

CODE2

Code:

echo "$XXCU_DATA_TOP/AP/in/123"
cd $XXCU_DATA_TOP/AP/in/123
find . -type f -print -maxdepth 1 | sed -e 's;[^/]*/;|____;g;s;____|; |;g'

You said that you tried it with and without the touch -t option, but you only showed us that you used touch with no options. When you don't use the -t option, touch treats alls of the operands you give it as the names of files that are to be created (if they didn't already exist) or have their timestamps updated to the current time (if the did already exist).

If you're trying to figure out how to turn an input date operand in the form DD-MON-YYYY into a touch -t option-argument in the form YYYYMMDDhhmm we need to know what operating system and shell you're using to be able to specify a simple (or complex) method that will work in your environment.

Do you want help (which has been given to you) or prefer to be spoon-fed with a ready made solution?

By testing and understanding the proposals given and adapting them into your own code you should be able to solve your problem. Did you compare your find command to the one given by Yoda including all options and parameters?

Hi Rudic...Thanks for your help. I am using below code to get the number of days.

Code:

today_date=$(date +%d/%m/%Y) mm=$5 dd=$(date -d"$mm" +%d/%m/%Y) echo [[ $(( ($today_date - $dd) / (60 * 60 * 24) ))]]

. So I am getting below error " value too great for base (error token is "08")" I am having Todays Date: 16/10/2017 and Date From : 11/08/2017. I tried with adding 10# to the both the dates but still getting same error. Thanks in advance