Need to pass variable in a command and assign value to a variable
Hello All,
Hope you're doing well !
I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted.
Code:
header_date_14=$(m_dump /wload/baot/home/baotasa0/UKRB_UKBE/sandboxes/EXTRACTS/UK/RB/UKBA/ukrb_ukba_pbe_acq/dml/ukrb_ukba_acnt_bde27_src.dml $1 | head -35)
Any pointers will be greatly helpful !
Thank you !
Ekta
Moderator's Comments:
Please use CODE tags as required by forum rules!
Last edited by RudiC; 06-27-2017 at 05:12 AM..
Reason: Added CODE tags.
I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted.
You should never NEVER use constructs like $1 directly in your code. You see, $1, $2, etc. are positional parameters, not variables. $1 isn't the name of a variable just happening to have the name "1", like "$foo", it is the first parameter passed to this specific context - and what "this specific context" means can change (and does so) from context to context.
This also gives you the opportunity to give a meaningful name to the variable like "inputfile", instead of "$1", which won't tell you by its name what it is supposed to contain.
Below is the command, which is used for accessing multi files, what I was trying to do is to pass the name of the file as an argument, which is highlighted below -
m_dump /wload/baot/home/baotasa0/UKRB_UKBE/sandboxes/EXTRACTS/UK/RB/UKBA/ukrb_ukba_pbe_acq/dml/ukrb_ukba_acnt_bde27_src.dml bdfo27m_a016_19122014_V1.dat | head -35
This should give me something similar to what is mentioned below -
Record 1:
This request is different from the one in post#1. You didn't give us any hint on what might go wrong with your approach. The head -35 obviously prints mere 29 lines. IS anything ELSE going wrong? SHOULD this give you something similar, or DOES it?
which is of 35 lines and constitues to first record of the file we are trying to read using m_dump, I need to place the file name using command line and as per Bakunin's suggestion I tried using below code but it did not work -
Code:
param1 = $inputfile1
param2 = $inputfile2
param3 = $inputfile3
header_date_14=$(m_dump /wload/baot/app/data_abinitio/serial/uk_cust/ukrb_ukba_acnt_bde27_src.dml $'$param1' | head -35)
header_date_15=$(m_dump /wload/baot/app/data_abinitio/serial/uk_cust/ukrb_ukba_acnt_bde27_src.dml $'$param2' | head -35)
header_date_16=$(m_dump /wload/baot/app/data_abinitio/serial/uk_cust/ukrb_ukba_acnt_bde27_src.dml $'$param3' | head -35)
Once this command is executed, I need to take out bdfo_run_date 41991 to display it...
Neither of my questions has been answered, none of my suggestions was applied, helpful info was not supplied. Instead of focusing on one problem (specified in the first post), you are broadening the operating field and introduce new errors. In your last post, there are at least two syntactical errors: spaces around the equals signs when assigning shell variables, and single quotes around the variables preventing them from being expanded. No surprise it doesn't do what you expect.
Unless you supply info enabling people to help you, I'm afraid I can't help further.
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06-27-2017
