Loop with command line arguments


 
Thread Tools Search this Thread
Top Forums UNIX for Beginners Questions & Answers Loop with command line arguments
# 8  
Old 12-27-2016
Hi guys!,

I'm late, sorry, but I need time to try your suggestions! and more time to add them to my pipeline and verify if the whole thing works...

It works, thanks a lot !!! I used "shift"... shift -> for (do ... done) ...

Many thanks !!!
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Command line arguments for addition

Hi all, I am trying to write a code for addition of n numbers which will be passed by the user as command line arguments. I wrote the following code. add=0 for (( i = 1 ; i <= $# ; i++ )) do add=`expr $i + $add` done #echo "sum is : $add" input : $./add.sh 12 32 14... (7 Replies)
Discussion started by: PranavEcstasy
7 Replies

2. Shell Programming and Scripting

command line arguments

hi,,,, I want to create a command prompt, for example "prompt>", so my prompt need to handle commands, for example "prompt>cmd", so i want to know how to get arguments for my own commands cmd, i.e. default argc should contain arguments count and argv should point to the argument vector i.e, for... (2 Replies)
Discussion started by: vins_89
2 Replies

3. Shell Programming and Scripting

Command Line Arguments - not working

I am new to the world of Unix and shell scripting and have been trying to get the following simple script to work: #!/bin/bash echo "what is your age?" echo "you are $1 years old"I want to be able to enter my age on the command line, when prompted, and it return the... (1 Reply)
Discussion started by: meursault
1 Replies

4. UNIX for Dummies Questions & Answers

command line arguments

hi, can someone how to accept command line arguments as a variable using in script? like: ./scriptname arguments by accept arguments, I can use it in my script? thx! (1 Reply)
Discussion started by: ikeQ
1 Replies

5. UNIX for Dummies Questions & Answers

Command line arguments.

I am working on a script wherein i need the user to enter the Build ID for eg:the command line will show enter the build ID Now on entering the build ID it should be assigned to @ARGV. How can this be done.? (1 Reply)
Discussion started by: Varghese
1 Replies

6. Shell Programming and Scripting

command line arguments

-------------------------------------------------------------------------------- I have this while loop and at the end I am trying to get it to tell me the last argument I entered. And with it like this all I get is the sentence with no value for $1. Now I tried moving done after the sentence... (1 Reply)
Discussion started by: skooly5
1 Replies

7. Shell Programming and Scripting

i want to list all command line arguments except

Hi all i want to list out all command line arguments except $1 i have passed to a script. Ex: sh cmdline.sh one two three four five o/p: two three four five (3 Replies)
Discussion started by: naree
3 Replies

8. UNIX for Dummies Questions & Answers

arguments in command line

Hi all, How many arguments can we pass while testing a prgm at command line.. I encountered an issue while passing 10 arguments. For $10 its taking argument passed for $1 followed by 'zero'. can we pass more than 9 arguments /Is there any other way. Thanks, rrs (6 Replies)
Discussion started by: rrs
6 Replies

9. Programming

command line arguments

Hi How to pass multi line text as a command line argument to a program. (i.e) ./a.out hi this is sample 0 file1 where hi this is sample should be stored in argv 0 in argv and so on... (3 Replies)
Discussion started by: bankpro
3 Replies

10. UNIX for Advanced & Expert Users

Parsing the command line arguments

Is there a way to get the command line arguments. I am using getopt(3) but if the arguments are more than one for a particular option than it just ignores the second argument. For eg ./a.out -x abc def now abd will be got with -x using getopt "( x : )" and string abc\0def will get stored... (7 Replies)
Discussion started by: jayakhanna
7 Replies
Login or Register to Ask a Question
IO::Async::Loop::Epoll(3pm)				User Contributed Perl Documentation			       IO::Async::Loop::Epoll(3pm)

NAME
IO::Async::Loop::Epoll - use "IO::Async" with "epoll" on Linux SYNOPSIS
use IO::Async::Loop::Epoll; use IO::Async::Stream; use IO::Async::Signal; my $loop = IO::Async::Loop::Epoll->new(); $loop->add( IO::Async::Stream->new( read_handle => *STDIN, on_read => sub { my ( $self, $buffref ) = @_; while( $$buffref =~ s/^(.*) ? // ) { print "You said: $1 "; } }, ) ); $loop->add( IO::Async::Signal->new( name => 'INT', on_receipt => sub { print "SIGINT, will now quit "; $loop->loop_stop; }, ) ); $loop->loop_forever(); DESCRIPTION
This subclass of IO::Async::Loop uses IO::Epoll to perform read-ready and write-ready tests so that the O(1) high-performance multiplexing of Linux's epoll_pwait(2) syscall can be used. The "epoll" Linux subsystem uses a registration system similar to the higher level IO::Poll object wrapper, meaning that better performance can be achieved in programs using a large number of filehandles. Each epoll_pwait(2) syscall only has an overhead proportional to the number of ready filehandles, rather than the total number being watched. For more detail, see the epoll(7) manpage. This class uses the epoll_pwait(2) system call, which atomically switches the process's signal mask, performs a wait exactly as epoll_wait(2) would, then switches it back. This allows a process to block the signals it cares about, but switch in an empty signal mask during the poll, allowing it to handle file IO and signals concurrently. CONSTRUCTOR
$loop = IO::Async::Loop::Epoll->new() This function returns a new instance of a "IO::Async::Loop::Epoll" object. METHODS
As this is a subclass of IO::Async::Loop, all of its methods are inherited. Expect where noted below, all of the class's methods behave identically to "IO::Async::Loop". $count = $loop->loop_once( $timeout ) This method calls the "poll()" method on the stored "IO::Epoll" object, passing in the value of $timeout, and processes the results of that call. It returns the total number of "IO::Async::Notifier" callbacks invoked, or "undef" if the underlying "epoll_pwait()" method returned an error. If the "epoll_pwait()" was interrupted by a signal, then 0 is returned instead. SEE ALSO
o IO::Epoll - Scalable IO Multiplexing for Linux 2.5.44 and higher o IO::Async::Loop::Poll - use IO::Async with poll(2) AUTHOR
Paul Evans <leonerd@leonerd.org.uk> perl v5.14.2 2012-04-10 IO::Async::Loop::Epoll(3pm)