I understood that already. Now, such a task breaks down to two parts: first, write a script which takes a certain directory name and then executes the task you described below for that one directory (respectively the files in this directory). The second part is to create a list of these directories and then call the script with each of these directory names as arguments.
You probably have overseen my mentioning of the find-command. It has everything you need to do this second part (creating a list of directory names) and i suggest you follow the link i gave you and find out how it works. Once you get that covered we will find out how to write a script which does what you want for one directory supplied on the commandline.
bakunin
Perhaps there is some misunderstanding on my part. I'm including screenshots to make sure I did not describe something incorrectly. I went ahead and made a list of all the folders in the directory. Please see below if I have done it correctly.
[QUOTE=MadeInGermany;302974553]Instead of cd `echo $CASE` you simply do cd "$CASE".
Instead of "cd" you can use "pushd" and return to the previous directory with "popd".
Code:
foreach ...
pushd "$CASE"
dtifit ...
popd
end
You are using csh; instead I recommend to go to bash or ksh. Then, instead of the pushd/popd you can use a ( sub shell ) where the "cd" happens only in the sub shell and the current directory in the main shell is unchanged
Hmm, pardon my lack of knowledge, but does echo and $ in CASE do the same thing?
for a in `find . -type d`
do
cd $a
yourlogic
cd <lcoation of the script where it is>
done
This will into all the directories and their sub-directories and apply your logic but you need to come base directory in the script hence i have used cd before the done command.
Code:
for a in `find . -type d`
do
for b in filename1 filename2 --> if known else you could use below statement
for b in `ls -l $a| grep ^-| awk '{print $0}'` --> this will check all files in the of variable a.
your logic with $a/$b --> Your file to apply logic
done
done
Moderator's Comments:
Please use code tags as required by forum rules! Even for pseudo code.
Last edited by RudiC; 06-08-2016 at 01:31 PM..
Reason: Added code tags.
Hmm, pardon my lack of knowledge, but does echo and $ in CASE do the same thing?
I am not sure if I understand your question.
Here are some explanations: $CASE gives the value of the variable CASE. echo $CASE prints the value of the variable. The value is evaluated before (for example, a * character is a wildcard and eventually replaced by matching files in the current directory). Often you don't want that, then put it in quotes: echo "$CASE".
Instead of printing it with the echo command, you can cd to it with the cd command.
Now, the cd `echo "$CASE"` is complicated: it first does an echo "$CASE", but because it is in backticks it does not print to the screen but is passed to the cd command.
for a in `find . -type d`
do
cd $a
yourlogic
cd <lcoation of the script where it is>
done
This will into all the directories and their sub-directories and apply your logic but you need to come base directory in the script hence i have used cd before the done command.
Code:
for a in `find . -type d`
do
for b in filename1 filename2 --> if known else you could use below statement
for b in `ls -l $a| grep ^-| awk '{print $0}'` --> this will check all files in the of variable a.
your logic with $a/$b --> Your file to apply logic
done
done
Moderator's Comments:
Please use code tags as required by forum rules! Even for pseudo code.
I'm sorry to sound so novice but could you explain how I would modify the code to use the filenames that I have in the first post of this thread? Also, I'm confused as to what to put in the 'your logic' part, if you could please explain it further, it would be very helpful.
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06-08-2016
