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Command to get URL under string "SIT"

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Top Forums UNIX for Beginners Questions & Answers Command to get URL under string "SIT"
# 8  
Old 02-17-2016
Quote:
Originally Posted by RudiC
@Don Cragun: Please explain awk '/"SIT"/+1 && /https:/' *.xml
Ouch! Thank you for catching the problem.

I mistakenly thought /"SIT"/+1 was selecting the line following a line containing "SIT" and the /https:/ would be true on those lines that contained https: causing that line to be printed.

The following seems to correctly do what I was trying to do:
Code:
awk 'n && /https:/;n = /"SIT"/{}' *.xml

# 9  
Old 02-17-2016
Hahaha - I was trying and testing to and fro to find out what you meant and what the trick was...
# 10  
Old 02-17-2016
Quote:
Originally Posted by rockingvj
Thanks Don. The operating system I'm using is LINUX.

I can see its printing the URL under SIT, but I forgot to mention that I need to search under different folders and so I have used below command

Code:
find . -name "*.xml" |xargs grep -A1 "SIT" | grep 'https'

It is actually printing everything , so I need values of folder which has
Code:
*.xml

and go into that and get URL which is under SIT.
I don't understand what you are saying here.

With the sample input you showed us, exactly what output are you trying to produce?

If the input you showed us was incomplete or not representative of your actual input, please provide a new example clearly explaining what you are trying to do AND show us the exact output you are trying to produce from that expanded example.
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