Grep output


 
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# 1  
Old 01-08-2016
Grep output

Hi.
I have a command line that will generate exif data from .jpg files...
So to get the Camera Model I use:
Code:
find -iname "*.jpg" -print0 | xargs -0 exiftool -a | grep "Camera Model"

But I want the file name AND the camera model... How to I get the grep to give me TWO bits of information from the output???

All help gratefully accepted.

---------- Post updated at 05:01 PM ---------- Previous update was at 04:46 PM ----------

I suppose the real question is really: regardless of what information is being input to grep, how (or can you) extract more than one item of data from that input?

Last edited by vbe; 01-08-2016 at 04:17 PM.. Reason: code tags please even for so lttle...
# 2  
Old 01-08-2016
Use egrep.

Code:
find -iname "*.jpg" -print0 | xargs -0 exiftool -a | egrep 'Camera Model|File Name'


Last edited by RavinderSingh13; 09-15-2019 at 10:09 AM..
This User Gave Thanks to smurphy_it For This Post:
# 3  
Old 01-08-2016
Thanks Smurphy! It's a LONG time since my basic Unix days. I completely forgot about egrep!
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