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Help in find and replace.

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Top Forums UNIX for Advanced & Expert Users Help in find and replace.
# 15  
Old 06-25-2008
Hi!
Following is the output:

Code:
[root@catinfo conf]# /opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha tomcat
tomcat:536c0b339345616c1b33caf454454d8b8a190d6c
[root@catinfo conf]#

# 16  
Old 06-25-2008
Give this a try:

Code:
perl -i.bak -pe'
s/(password=")([^"]*)/$1.`/opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha $2|cut -d: -f2|tr -d "\n"`/e
' tomcat-users.xml

P.S. I'm trying to figure out how to parse within perl the output returned by the ` ` construct. I'm sure cut and tr are redundant.
# 17  
Old 06-25-2008
It shows some kind of syntax error for me..

Code:
[root@catinfo conf]# perl -i.bak -pe'
> s/(password=")([^"]*)/$1.`/opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha $2|cut -d: -f2|tr -d "\n"`/e
> ' tomcat-users.xml
Bareword found where operator expected at -e line 2, near "s/(password=")([^"]*)/$1.`/opt"
syntax error at -e line 2, near "s/(password=")([^"]*)/$1.`/opt"
Transliteration pattern not terminated at -e line 2.

# 18  
Old 06-25-2008
Could you try it like this:

Code:
perl -i.bak -pe'BEGIN { $cmd = "/opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha"; }
s/(password=")([^"]*)/
$1.`$cmd $2|cut -d: -f2|tr -d "\n"`
/e
' tomcat-users.xml

If it doesn't work, try it without tr:

Code:
perl -i.bak -pe'BEGIN { $cmd = "/opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha"; }
s/(password=")([^"]*)/
$1.`$cmd $2|cut -d: -f2`
/e
' tomcat-users.xml

Last edited by radoulov; 06-25-2008 at 08:24 AM..
# 19  
Old 06-25-2008
MySQL Hats off to you!! Works like a charm!!
The first one works like a charm!!!

radoulov, hats off to you!! You are guru!!

We really have some gurus on this forum!!

Thanks everyone for all the replies and giving me the right direction!!



nua7
# 20  
Old 06-25-2008
Glad it worked, but the code is ugly,
this should be more efficient (but still ugly):
Code:
perl -i.bak -pe'
  /password="([^"]*)/ and $pw = $1;
  $pw = `/opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha $pw`;
  chomp $pw; $pw =~ s/.*?://; s/(password=")([^"]*)/$1$pw/
  ' tomcat-users.xml

# 21  
Old 06-25-2008
I tried this command, but gives a syntax error to me..

Is it working fine at your end..?

Code:
[root@catinfo conf]# perl -i.bak -pe'
>   /password="([^"]*)/ and $pw = $1;
>   $pw = `/opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha $pw`;
>   chomp $pw; $pw =~ s/.*?://; s/(password=")([^"]*)/$1$pw/
>   ' tomcat-users.xml
sh: -c: line 0: syntax error near unexpected token `newline'
sh: -c: line 0: `/opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha  RealmBase -a <algorithm> [-e <encoding>] <credentials>'
sh: -c: line 0: syntax error near unexpected token `newline'
sh: -c: line 0: `/opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha  RealmBase -a <algorithm> [-e <encoding>] <credentials>'
sh: -c: line 0: syntax error near unexpected token `newline'
sh: -c: line 0: `/opt/coreservices/tomcat-5.5.9/bin/digest.sh -a sha  RealmBase -a <algorithm> [-e <encoding>] <credentials>'
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