UNIX for Advanced & Expert Users

AIX has ksh93, so the following should work

Code:

$ printf "%T\n" "01012008"
Tue Jan  1 20:08:00 EST 2008
$ printf "%T\n" "01012008 last saturday"
Sat Dec 29 20:08:00 EST 2007
$ printf "%T\n" "01012008 next sunday"
Sun Jan 13 20:08:00 EST 2008
$ printf "%T\n" "01012008 this sunday"
Sun Jan  6 20:08:00 EST 2008
$

Hello All for all your feedback.

I tried "fpmurphy" suggestion in regards to ksh93 but it doesn't appear that this has been installed on our aix server.

I did find a useful code that's doing a similar calculation to find "last Sunday" from an input date but it's written in Perl. Can someone assist me in converting it to a shell script? We also do not have Perl available here.

https://www.unix.com/unix-dummies-que...sing-perl.html

Thank you.

Humm, what version of AIX are you using?
What is the output of "print $KSH_VERSION" and "print ${.sh.version}"

AIX Version 5.2

$ print $KSH_VERSION

$ print ${.sh.version}
Version M-12/28/93e

I tried your example below and I get the following error:

printf "%T\n" "01012008"
ksh93: printf: T: unknown format specifier

Thank you.

You indeed have ksh93 installed but it is a very old version. That particular version was release at the end of July 1996. I believe that you need version h or better (released in 1999) for "%T" functionality.

Thanks fpmurphy for your quick reply....

Unfortunately, I'm not part of the Unix team system administrators and whichever versions they decide to install on the server is up to them.

So, is there any other options for me???

I'm thinking of a potential solution - can you let me know if this will work or not?

Question: For any given date, get previous Saturday's date.

Solution: Current date => convert to julian date (A)
(for example: 205 for today's date)

Current date => get day of the week (B)
(for example: 3 for today's date)

Previous Saturday = (A)-(B)-1 (since sunday = 0) <= (205 - 3)-1 = 201

Then convert julian date format back to calendar date format.....is there an easy way to do this?

Thanks.