UNIX for Advanced & Expert Users

Hi

i am using grep command to search a string in a file and i am able to find that string in it ..

but moving forward once i find the string i need to remove the 5 lines above that and to remove 2 lines below it .. Just wanted to be clear there should be no lines existing which has a string coys11

Example :

file1.txt
cat435
gggte
werwr
coys11
ewrer

when i run this script , it should delete all the lines above it and lines below it

Thanks.. Please do help me on this .. Thanks again..!!

Hi

i am using grep command to search a string in a file and i am able to find that string in it ..

but moving forward once i find the string i need to remove the 5 lines above that and to remove 2 lines below it .. Just wanted to be clear there should be no lines existing which has a string coys11

Example :

file1.txt
cat435
gggte
werwr
coys11
ewrer

when i run this script , it should delete all the lines above it and lines below it

Thanks.. Please do help me on this .. Thanks again..!!

Hey
why dont you use sed ?
sed '/^[Cc]oys11/p' Filename

Hope this is what you want !!

Thanks !

I thing this one removes not just "coys11" it removes all the line which inherits c,o,y,s,1.

if he just want to remove just coys11
grep -v -w joys11 inpufile is better. But I thing he wants something else

let's say your file looks like this;
.
.
.
aa
bb
cc
dd
ee
ff
gg
hh
ii
jj
kk
.
.

and let's say your string is gg
do you want to remove bb-ii (including bb,gg,ii) ? if it is;

currentline=`grep -n string inputfile|awk ' {print $1} '`
let "startingline=$currentline-5"
let "finishingline=$currentline+2"

sed -n "$startingline,${finishingline}!s/.*/&/p" inputfile>outfile

Hi

Thanks for the replies

Just wanted to be clear

lets assume i have a file1.txt which has the following

aaa
bbb
bbb
ccc
qqq
343
454
eee

i am looking for a string 343 once the script finds 343 it should delete 4 lines above it and 2 lines below it

the output file should be

qqq

Thanks

is there any line before aaa and after eee in the file ?

if there is not than the code is;

let "currentline=`grep -n string inputfile|awk -F ':' {print $1} '`-1"
sed -n "${currentline}s/.*/&/p" inputfile>outfile

if there is. it is a bit harder .The code is ;

let "currentline=`grep -n string inputfile|awk -F ':' ' {print $1} '`-1"
let "fisrtpart=$currentline-5"
let "secondpart=$currentline+4"
sed -n "1,${firstpart}s/.*/&/p" inputfile>outfile
sed -n "${currentline}s/.*/&/p" inputfile>>outfile
sed -n "$secondpart,\$s/.*/&/p" inputfile>>outfile